A shuttle cork hitted upward from badminton racket with a velocity of 50 m/s and it reaches 3 m from the hitting point in last seconds of its upward journey. If the same shuttle cork is hitted upward with a velocity of 200 m/s, then what will be the distance travelled in last second of its upward journey?

Question

Answer

Problem:

A shuttle cork is hit upward from a badminton racket with a velocity of 50 m/s and it reaches 3 m from the hitting point in the last second of its upward journey. If the same shuttle cork is hit upward with a velocity of 200 m/s, then what will be the distance travelled in the last second of its upward journey?

Solution:

Step 1: Calculate the time taken by the shuttle cork to reach the maximum height.

When a shuttle cork is hit upward, it follows a projectile motion. The time taken by the shuttle cork to reach the maximum height can be calculated using the following formula:

Time taken to reach the maximum height, t = u/g where,

u = initial velocity = 50 m/s

g = acceleration due to gravity = 9.8 m/s²

Therefore, t = 50/9.8 = 5.1 seconds.

Step 2: Calculate the maximum height reached by the shuttle cork.

The maximum height reached by the shuttle cork can be calculated using the following formula:

Maximum height, h = u²/2g where,

u = initial velocity = 50 m/s

g = acceleration due to gravity = 9.8 m/s²

Therefore, h = 50²/2 x 9.8 = 127.55 meters.

Step 3: Calculate the velocity of the shuttle cork at the maximum height.

The velocity of the shuttle cork at the maximum height can be calculated using the following formula:

Velocity at maximum height, v = 0 m/s (as the shuttle cork stops at the maximum height)

Step 4: Calculate the time taken by the shuttle cork to reach 3 meters from the hitting point.

The time taken by the shuttle cork to reach 3 meters from the hitting point can be calculated using the following formula:

Distance travelled in the last second, s = 3 meters

Time taken to travel the last second, t₁ = 1 second

Time taken to travel the remaining distance, t₂ = t - t₁ = 5.1 - 1 = 4.1 seconds

Therefore, the distance travelled by the shuttle cork in the last 4.1

Answer

Is 6 meter answer??

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