A shuttle cork hitted upwards from badminton racket with a v 50 m/s and it reaches 3 m from the hitting the last seconds of its upward journey. If the same shuttle cork is hitted up with v 200 m/s then wht will be the distance travelled in last seconds of journey ?

Question

Answer

Problem Statement:

A shuttle cork is hit upwards from a badminton racket with a velocity of 50 m/s. It reaches a height of 3 m from the point of hitting in the last seconds of its upward journey. If the same shuttle cork is hit upwards with a velocity of 200 m/s, what will be the distance travelled in the last seconds of its journey?

Solution:

Understanding the motion of the shuttle cork:

The motion of the shuttle cork can be divided into two parts:

Upward motion

Downward motion

During the upward motion, the shuttle cork travels against the force of gravity. As it reaches the highest point of its motion, its velocity becomes zero. During the downward motion, the shuttle cork travels in the direction of the force of gravity. Its velocity increases until it hits the ground.

Calculating the time of flight:

Let us first calculate the time of flight of the shuttle cork when it is hit upwards with a velocity of 50 m/s.

Using the kinematic equation,

Final Velocity = Initial Velocity + Acceleration x Time

where,

Final Velocity = 0 m/s (at the highest point of motion)

Initial Velocity = 50 m/s

Acceleration = -9.8 m/s^2 (due to gravity, it acts downward)

Substituting these values in the equation,

0 = 50 - 9.8 x Time

Time = 5.1 seconds

Therefore, the time of flight of the shuttle cork is 5.1 seconds.

Calculating the height reached:

Using the kinematic equation,

Final Velocity^2 - Initial Velocity^2 = 2 x Acceleration x Height

where,

Final Velocity = 0 m/s (at the highest point of motion)

Initial Velocity = 50 m/s

Acceleration = -9.8 m/s^2 (due to gravity, it acts downward)

Height = 3 m (the height reached by the shuttle cork in the last seconds of its upward journey)

Substituting these values in the equation,

0^2 - 50^2 = 2 x (-9.8) x 3

98 = 19.6 x Height

Height = 5 meters

Calculating the distance travelled:

During the last seconds of its upward journey, the shuttle cork travels a distance of 5 meters. This distance is equal to the maximum height reached by the shuttle cork.

Now, let us calculate the distance travelled by the shuttle cork when it is hit upwards with a velocity of 200 m/s.

Using the same

Answer

Is answer 48m

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