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Radha moves towards South-East a distance of 7 km, then she moves towards West and travels a distance of 14 km. From here she moves towards North-West a distance of 7 km and finally she moves a distance of 4 km towards east. How far is she now from the starting point?

  • a)
    3 km

  • b)
    4 km

  • c)
    10 km

  • d)
    11 km

Correct answer is option 'C'. Can you explain this answer?
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Radha moves towards South-East a distance of 7 km, then she moves towa...
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Radha moves towards South-East a distance of 7 km, then she moves towa...
Given information:
- Radha moves towards South-East a distance of 7 km.
- She moves towards West and travels a distance of 14 km.
- From here she moves towards North-West a distance of 7 km.
- Finally, she moves a distance of 4 km towards east.

To find: How far is she now from the starting point?

Solution:
Let's assume that the starting point is denoted by O and the final position of Radha is denoted by P. We need to find the distance OP.

- Let's draw a rough diagram to understand the movements of Radha.

```
N
|
W ----- O ----- E
|
S
```

- Radha moves towards South-East a distance of 7 km. This means she moves towards the bottom-right direction from O and reaches a point A.
- She moves towards West and travels a distance of 14 km. This means she moves towards the left direction from A and reaches a point B.
- From here she moves towards North-West a distance of 7 km. This means she moves towards the top-left direction from B and reaches a point C.
- Finally, she moves a distance of 4 km towards east. This means she moves towards the right direction from C and reaches the final position P.

- Let's draw another rough diagram to understand the final position of Radha.

```
N
|
W ------ O ------ P (4 km towards East)
|
S
```

- From the above diagram, we can see that the distance OP is the hypotenuse of the right-angled triangle OCP.
- Let's find the length of OC and CP using Pythagoras theorem.

OC^2 = OA^2 + AC^2 (as triangle OAC is a right-angled triangle)
OC^2 = 7^2 + 7^2 = 98
OC = sqrt(98) = 7sqrt(2)

CP^2 = PC^2 = 4^2 = 16

- Therefore, OP^2 = OC^2 + CP^2
OP^2 = (7sqrt(2))^2 + 16
OP^2 = 98 + 16
OP^2 = 114
OP = sqrt(114) = 10.68 km (approx.)

Therefore, Radha is now approximately 10.68 km away from the starting point.

Hence, the correct answer is option (c) 10 km.
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Radha moves towards South-East a distance of 7 km, then she moves towards West and travels a distance of 14 km. From here she moves towards North-West a distance of 7 km and finally she moves a distance of 4 km towards east. How far is she now from the starting point?a)3 kmb)4 kmc)10 kmd)11 kmCorrect answer is option 'C'. Can you explain this answer?
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