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Radha moves towards South-East a distance of 7 km, then she moves towards West and travels a distance of 14 km. From here she moves towards North-West a distance of 7 km and finally she moves a distance of 4 km towards east. How far is she now from the starting point?
- a)3 km
- b)4 km
- c)10 km
- d)11 km
Correct answer is option 'C'. Can you explain this answer?
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Radha moves towards South-East a distance of 7 km, then she moves towa...
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Radha moves towards South-East a distance of 7 km, then she moves towa...
Given information:
- Radha moves towards South-East a distance of 7 km.
- She moves towards West and travels a distance of 14 km.
- From here she moves towards North-West a distance of 7 km.
- Finally, she moves a distance of 4 km towards east.
To find: How far is she now from the starting point?
Solution:
Let's assume that the starting point is denoted by O and the final position of Radha is denoted by P. We need to find the distance OP.
- Let's draw a rough diagram to understand the movements of Radha.
```
N
|
W ----- O ----- E
|
S
```
- Radha moves towards South-East a distance of 7 km. This means she moves towards the bottom-right direction from O and reaches a point A.
- She moves towards West and travels a distance of 14 km. This means she moves towards the left direction from A and reaches a point B.
- From here she moves towards North-West a distance of 7 km. This means she moves towards the top-left direction from B and reaches a point C.
- Finally, she moves a distance of 4 km towards east. This means she moves towards the right direction from C and reaches the final position P.
- Let's draw another rough diagram to understand the final position of Radha.
```
N
|
W ------ O ------ P (4 km towards East)
|
S
```
- From the above diagram, we can see that the distance OP is the hypotenuse of the right-angled triangle OCP.
- Let's find the length of OC and CP using Pythagoras theorem.
OC^2 = OA^2 + AC^2 (as triangle OAC is a right-angled triangle)
OC^2 = 7^2 + 7^2 = 98
OC = sqrt(98) = 7sqrt(2)
CP^2 = PC^2 = 4^2 = 16
- Therefore, OP^2 = OC^2 + CP^2
OP^2 = (7sqrt(2))^2 + 16
OP^2 = 98 + 16
OP^2 = 114
OP = sqrt(114) = 10.68 km (approx.)
Therefore, Radha is now approximately 10.68 km away from the starting point.
Hence, the correct answer is option (c) 10 km.
- Radha moves towards South-East a distance of 7 km.
- She moves towards West and travels a distance of 14 km.
- From here she moves towards North-West a distance of 7 km.
- Finally, she moves a distance of 4 km towards east.
To find: How far is she now from the starting point?
Solution:
Let's assume that the starting point is denoted by O and the final position of Radha is denoted by P. We need to find the distance OP.
- Let's draw a rough diagram to understand the movements of Radha.
```
N
|
W ----- O ----- E
|
S
```
- Radha moves towards South-East a distance of 7 km. This means she moves towards the bottom-right direction from O and reaches a point A.
- She moves towards West and travels a distance of 14 km. This means she moves towards the left direction from A and reaches a point B.
- From here she moves towards North-West a distance of 7 km. This means she moves towards the top-left direction from B and reaches a point C.
- Finally, she moves a distance of 4 km towards east. This means she moves towards the right direction from C and reaches the final position P.
- Let's draw another rough diagram to understand the final position of Radha.
```
N
|
W ------ O ------ P (4 km towards East)
|
S
```
- From the above diagram, we can see that the distance OP is the hypotenuse of the right-angled triangle OCP.
- Let's find the length of OC and CP using Pythagoras theorem.
OC^2 = OA^2 + AC^2 (as triangle OAC is a right-angled triangle)
OC^2 = 7^2 + 7^2 = 98
OC = sqrt(98) = 7sqrt(2)
CP^2 = PC^2 = 4^2 = 16
- Therefore, OP^2 = OC^2 + CP^2
OP^2 = (7sqrt(2))^2 + 16
OP^2 = 98 + 16
OP^2 = 114
OP = sqrt(114) = 10.68 km (approx.)
Therefore, Radha is now approximately 10.68 km away from the starting point.
Hence, the correct answer is option (c) 10 km.
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Radha moves towards South-East a distance of 7 km, then she moves towards West and travels a distance of 14 km. From here she moves towards North-West a distance of 7 km and finally she moves a distance of 4 km towards east. How far is she now from the starting point?a)3 kmb)4 kmc)10 kmd)11 kmCorrect answer is option 'C'. Can you explain this answer?
Question Description
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Solutions for Radha moves towards South-East a distance of 7 km, then she moves towards West and travels a distance of 14 km. From here she moves towards North-West a distance of 7 km and finally she moves a distance of 4 km towards east. How far is she now from the starting point?a)3 kmb)4 kmc)10 kmd)11 kmCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for LR.
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Radha moves towards South-East a distance of 7 km, then she moves towards West and travels a distance of 14 km. From here she moves towards North-West a distance of 7 km and finally she moves a distance of 4 km towards east. How far is she now from the starting point?a)3 kmb)4 kmc)10 kmd)11 kmCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Radha moves towards South-East a distance of 7 km, then she moves towards West and travels a distance of 14 km. From here she moves towards North-West a distance of 7 km and finally she moves a distance of 4 km towards east. How far is she now from the starting point?a)3 kmb)4 kmc)10 kmd)11 kmCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Radha moves towards South-East a distance of 7 km, then she moves towards West and travels a distance of 14 km. From here she moves towards North-West a distance of 7 km and finally she moves a distance of 4 km towards east. How far is she now from the starting point?a)3 kmb)4 kmc)10 kmd)11 kmCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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