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The wave described by y = 0.25 sin (10πx – 2πt), where x and y are in meters and t in seconds, is a wave travelling along the: [2008]
  • a)
    –ve x direction with frequency 1 Hz.
  • b)
    +ve x direction with frequency λ Hz and wavelength λ = 0. 2 m
  • c)
    +ve x direction with frequency 1 Hz and wavelength λ = 0.2 m
  • d)
    –ve x direction with amplitude 0.25 m and wavelength λ = 0.2 m
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The wave described by y = 0.25 sin (10πx – 2πt), where x a...
y = 0.25 sin (10πx – 2πt)
Comparing this equation with the standard wave equation y = asin (kx – ωt)
We get,  k = 10π
And ω = 2π or, 2πv = 2π ⇒ v = 1Hz.
The sign inside the bracket is negative, hence the wave travels in + ve x- direction.
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Most Upvoted Answer
The wave described by y = 0.25 sin (10πx – 2πt), where x a...
The wave described by y = 0.25 sin (10x) is a sinusoidal wave that oscillates with an amplitude of 0.25 units. The wave has a period of 2π/10, which is approximately 0.628 units. The wave is centered around the x-axis and oscillates between positive and negative values. The value of y at any given point x can be determined by plugging the x-coordinate into the equation and evaluating the sine function.
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The wave described by y = 0.25 sin (10πx – 2πt), where x and y are in meters and t in seconds, is a wave travelling along the: [2008]a)–ve x direction with frequency 1 Hz.b)+ve x direction with frequency λ Hz and wavelength λ = 0. 2 mc)+ve x direction with frequency 1 Hz and wavelength λ = 0.2 md)–ve x direction with amplitude 0.25 m and wavelength λ = 0.2 mCorrect answer is option 'C'. Can you explain this answer?
Question Description
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