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A particle is moving in a straight line such that its velocity varies as v =v0 e-lemda t, where lemda and t are constant. Find the average velocity during the time interval in which the velocity decrease from v0 to v0/2?
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A particle is moving in a straight line such that its velocity varies ...
Introduction:
In this problem, we are given the velocity of a particle as a function of time. We need to find the average velocity of the particle during the time interval in which the velocity decreases from v0 to v0/2.

Derivation:
The velocity of the particle is given by v = v0 e^-λt

Let's find the time taken for the velocity to decrease from v0 to v0/2.

v = v0/2

v0 e^-λt = v0/2

e^-λt = 1/2

-λt = ln(1/2)

-λt = -ln2

t = ln2/λ

Now, we need to find the average velocity of the particle during the time interval from t=0 to t=ln2/λ.

Solution:

Step 1: Find the displacement of the particle during the time interval from t=0 to t=ln2/λ.

The displacement of the particle during this time interval is given by:

Δx = ∫v0/2v0 v(t) dt

= ∫v0/2v0 v0 e^-λt dt

= -v0/λ [e^-λt]v0/2v0

= -v0/λ [e^-(λln2/λ) - 1]

= -v0/λ [1/2 - 1]

= v0/λ [1/2]

Δx = v0/2λ

Step 2: Find the time taken for the particle to travel from v0 to v0/2.

The time taken for the particle to travel from v0 to v0/2 is given by:

t = ln2/λ

Step 3: Find the average velocity of the particle during the time interval from t=0 to t=ln2/λ.

The average velocity of the particle during this time interval is given by:

v_avg = Δx / t

v_avg = (v0/2λ) / (ln2/λ)

v_avg = v0/2 ln2

Conclusion:
Therefore, the average velocity of the particle during the time interval in which the velocity decreases from v0 to v0/2 is v0/2 ln2.
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A particle is moving in a straight line such that its velocity varies ...
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A particle is moving in a straight line such that its velocity varies as v =v0 e-lemda t, where lemda and t are constant. Find the average velocity during the time interval in which the velocity decrease from v0 to v0/2?
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