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A particle of mass 2 kg Travels along a straight line with velocity V = a(x) ^1/2 where 'a' is constant. the work done by the net force during the displacement of particle from x = 0 to x=4m is?
Most Upvoted Answer
A particle of mass 2 kg Travels along a straight line with velocity V ...
Given:
- Mass of the particle, m = 2 kg
- Velocity of the particle, V = a(x) ^1/2
- Constant, a is given

Work Done Calculation:
1. The work done by the net force is given by the equation:
W = ∫F.dx = ∫m.a(x) ^1/2.dx
2. Given that force, F = m.a(x) ^1/2
3. Substituting the force in the work done equation, we get:
W = ∫m.a(x) ^1/2.dx
4. W = ∫2.a(x) ^1/2.dx from x = 0 to x = 4
5. W = 2∫a(x) ^1/2.dx from 0 to 4

Integrating with respect to x:
1. W = 2(2/3)a(x) ^3/2 from 0 to 4
2. W = 4/3 * a(4) ^3/2 - 4/3 * a(0) ^3/2
3. W = 4/3 * a(8) - 4/3 * a(0)
4. W = 32/3 * a
Therefore, the work done by the net force during the displacement of the particle from x = 0 to x = 4m is 32/3 * a.
Community Answer
A particle of mass 2 kg Travels along a straight line with velocity V ...
Is the ans 4a^2
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A particle of mass 2 kg Travels along a straight line with velocity V = a(x) ^1/2 where 'a' is constant. the work done by the net force during the displacement of particle from x = 0 to x=4m is?
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