NEET Exam > NEET Questions > A body of mass 0.5 kg travels in straight lin...
Start Learning for Free
A body of mass 0.5 kg travels in straight line with velocity v=ax^3/2. where a =5m-½s-¹.The work done by the net force during its displacement from x=0 to x=2m is.?
Most Upvoted Answer
A body of mass 0.5 kg travels in straight line with velocity v=ax^3/2....
Calculation of Work Done
The work done by the net force during the displacement of the body can be calculated using the work-energy principle.
Work-Energy Principle
According to the work-energy principle, the work done by the net force on a body is equal to the change in its kinetic energy.
Calculation of Kinetic Energy
The kinetic energy of the body can be calculated using the formula:
K.E. = 1/2 mv²
where m is the mass of the body and v is its velocity.
Calculation of Velocity
The velocity of the body can be calculated using the given formula:
v = ax³/²
where a = 5m-½s-¹
We can substitute the value of a in the formula to get:
v = 5(x³/²)m/s
Calculation of Kinetic Energy (Continued)
Substituting the value of v in the formula for kinetic energy, we get:
K.E. = 1/2 (0.5 kg) (5(x³/²) m/s)²
K.E. = 6.25x⁶ J
Calculation of Work Done
The work done by the net force during the displacement of the body from x = 0 to x = 2m can be calculated as follows:
W = ΔK.E.
W = K.E.(final) - K.E.(initial)
W = (6.25(2³) J) - (6.25(0³) J)
W = 62.5 J
Therefore, the work done by the net force during the displacement of the body from x = 0 to x = 2m is 62.5 J.
The work done by the net force during the displacement of the body can be calculated using the work-energy principle.
Work-Energy Principle
According to the work-energy principle, the work done by the net force on a body is equal to the change in its kinetic energy.
Calculation of Kinetic Energy
The kinetic energy of the body can be calculated using the formula:
K.E. = 1/2 mv²
where m is the mass of the body and v is its velocity.
Calculation of Velocity
The velocity of the body can be calculated using the given formula:
v = ax³/²
where a = 5m-½s-¹
We can substitute the value of a in the formula to get:
v = 5(x³/²)m/s
Calculation of Kinetic Energy (Continued)
Substituting the value of v in the formula for kinetic energy, we get:
K.E. = 1/2 (0.5 kg) (5(x³/²) m/s)²
K.E. = 6.25x⁶ J
Calculation of Work Done
The work done by the net force during the displacement of the body from x = 0 to x = 2m can be calculated as follows:
W = ΔK.E.
W = K.E.(final) - K.E.(initial)
W = (6.25(2³) J) - (6.25(0³) J)
W = 62.5 J
Therefore, the work done by the net force during the displacement of the body from x = 0 to x = 2m is 62.5 J.
Community Answer
A body of mass 0.5 kg travels in straight line with velocity v=ax^3/2....
DW = F.ds = m a dsa = v {dv/ds} v= a' x^(3/2)a = v { d{a' x^(3/2)}/ds }a = v a' (3/2) x½ a = {a' x^(3/2)} * a' {3/2} x½a = (a')² x² {3/2}dW = m (a')² {x² ds} *{3/2}W = {3/2} m {(a')²} (1/3)[x³] W = {3/2}* {0.5} * {5²}*{1/3}*[2³-0³]W = 50 J {} number () power
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
A body of mass 0.5 kg travels in straight line with velocity v=ax^3/2. where a =5m-½s-¹.The work done by the net force during its displacement from x=0 to x=2m is.?
Question Description
A body of mass 0.5 kg travels in straight line with velocity v=ax^3/2. where a =5m-½s-¹.The work done by the net force during its displacement from x=0 to x=2m is.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body of mass 0.5 kg travels in straight line with velocity v=ax^3/2. where a =5m-½s-¹.The work done by the net force during its displacement from x=0 to x=2m is.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 0.5 kg travels in straight line with velocity v=ax^3/2. where a =5m-½s-¹.The work done by the net force during its displacement from x=0 to x=2m is.?.
A body of mass 0.5 kg travels in straight line with velocity v=ax^3/2. where a =5m-½s-¹.The work done by the net force during its displacement from x=0 to x=2m is.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body of mass 0.5 kg travels in straight line with velocity v=ax^3/2. where a =5m-½s-¹.The work done by the net force during its displacement from x=0 to x=2m is.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 0.5 kg travels in straight line with velocity v=ax^3/2. where a =5m-½s-¹.The work done by the net force during its displacement from x=0 to x=2m is.?.
Solutions for A body of mass 0.5 kg travels in straight line with velocity v=ax^3/2. where a =5m-½s-¹.The work done by the net force during its displacement from x=0 to x=2m is.? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A body of mass 0.5 kg travels in straight line with velocity v=ax^3/2. where a =5m-½s-¹.The work done by the net force during its displacement from x=0 to x=2m is.? defined & explained in the simplest way possible. Besides giving the explanation of
A body of mass 0.5 kg travels in straight line with velocity v=ax^3/2. where a =5m-½s-¹.The work done by the net force during its displacement from x=0 to x=2m is.?, a detailed solution for A body of mass 0.5 kg travels in straight line with velocity v=ax^3/2. where a =5m-½s-¹.The work done by the net force during its displacement from x=0 to x=2m is.? has been provided alongside types of A body of mass 0.5 kg travels in straight line with velocity v=ax^3/2. where a =5m-½s-¹.The work done by the net force during its displacement from x=0 to x=2m is.? theory, EduRev gives you an
ample number of questions to practice A body of mass 0.5 kg travels in straight line with velocity v=ax^3/2. where a =5m-½s-¹.The work done by the net force during its displacement from x=0 to x=2m is.? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup