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A human body required 0.01M activity ofradioactive substance after 24 hours. Half life ofradioactive substance is 6 hours. Then injectionof maximum activity of radioactive substance thatcan be injected will be [2001]
- a)0.08 M
- b)0.04 M
- c)0.32 M
- d)0.16 M
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A human body required 0.01M activity ofradioactive substance after 24 ...
Remaining activity = 0.01M
after 24 hrs
after 24 hrs
Initial activity = 0.01 × 16 = 0.16M
Most Upvoted Answer
A human body required 0.01M activity ofradioactive substance after 24 ...
Given Data:
- Initial activity required: 0.01M
- Half-life of the radioactive substance: 6 hours
- Time elapsed: 24 hours
Calculating the Final Activity:
- After 24 hours, the radioactive substance would have gone through 4 half-lives (24 hours / 6 hours per half-life).
- The final activity remaining after 24 hours can be calculated using the formula: Final Activity = Initial Activity * (1/2)^(number of half-lives).
- Final Activity = 0.01M * (1/2)^4 = 0.01M * (1/16) = 0.000625M
Maximum Activity that can be Injected:
- The maximum activity that can be injected would be the initial activity required to reach the desired activity after 24 hours.
- Since the final activity required after 24 hours is 0.000625M, the maximum activity that can be injected will be the initial activity required to achieve this.
- Initial Activity = Final Activity / (1/2)^(number of half-lives) = 0.000625M / (1/16) = 0.01M * 16 = 0.16M
Therefore, the maximum activity of the radioactive substance that can be injected is 0.16M. Hence, option D (0.16 M) is the correct answer.
- Initial activity required: 0.01M
- Half-life of the radioactive substance: 6 hours
- Time elapsed: 24 hours
Calculating the Final Activity:
- After 24 hours, the radioactive substance would have gone through 4 half-lives (24 hours / 6 hours per half-life).
- The final activity remaining after 24 hours can be calculated using the formula: Final Activity = Initial Activity * (1/2)^(number of half-lives).
- Final Activity = 0.01M * (1/2)^4 = 0.01M * (1/16) = 0.000625M
Maximum Activity that can be Injected:
- The maximum activity that can be injected would be the initial activity required to reach the desired activity after 24 hours.
- Since the final activity required after 24 hours is 0.000625M, the maximum activity that can be injected will be the initial activity required to achieve this.
- Initial Activity = Final Activity / (1/2)^(number of half-lives) = 0.000625M / (1/16) = 0.01M * 16 = 0.16M
Therefore, the maximum activity of the radioactive substance that can be injected is 0.16M. Hence, option D (0.16 M) is the correct answer.
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A human body required 0.01M activity ofradioactive substance after 24 hours. Half life ofradioactive substance is 6 hours. Then injectionof maximum activity of radioactive substance thatcan be injected will be [2001]a)0.08 Mb)0.04 Mc)0.32 Md)0.16 MCorrect answer is option 'D'. Can you explain this answer?
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A human body required 0.01M activity ofradioactive substance after 24 hours. Half life ofradioactive substance is 6 hours. Then injectionof maximum activity of radioactive substance thatcan be injected will be [2001]a)0.08 Mb)0.04 Mc)0.32 Md)0.16 MCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A human body required 0.01M activity ofradioactive substance after 24 hours. Half life ofradioactive substance is 6 hours. Then injectionof maximum activity of radioactive substance thatcan be injected will be [2001]a)0.08 Mb)0.04 Mc)0.32 Md)0.16 MCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A human body required 0.01M activity ofradioactive substance after 24 hours. Half life ofradioactive substance is 6 hours. Then injectionof maximum activity of radioactive substance thatcan be injected will be [2001]a)0.08 Mb)0.04 Mc)0.32 Md)0.16 MCorrect answer is option 'D'. Can you explain this answer?.
A human body required 0.01M activity ofradioactive substance after 24 hours. Half life ofradioactive substance is 6 hours. Then injectionof maximum activity of radioactive substance thatcan be injected will be [2001]a)0.08 Mb)0.04 Mc)0.32 Md)0.16 MCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A human body required 0.01M activity ofradioactive substance after 24 hours. Half life ofradioactive substance is 6 hours. Then injectionof maximum activity of radioactive substance thatcan be injected will be [2001]a)0.08 Mb)0.04 Mc)0.32 Md)0.16 MCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A human body required 0.01M activity ofradioactive substance after 24 hours. Half life ofradioactive substance is 6 hours. Then injectionof maximum activity of radioactive substance thatcan be injected will be [2001]a)0.08 Mb)0.04 Mc)0.32 Md)0.16 MCorrect answer is option 'D'. Can you explain this answer?.
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