Two block of mass 1kg nd 2kg are connected by a string AB of mass 1kg the blocks are placed on a smooth horizontal surface. Block of mass 1kg is pulled by a horizontal force F of 8N find tension in string at points A and B?

Question

Answer

Answer

Answer

Given information:
- Mass of block A (m1) = 1 kg
- Mass of block B (m2) = 2 kg
- Mass of string (m3) = 1 kg
- Horizontal force applied (F) = 8 N

Analysis:
- The blocks and the string are placed on a smooth horizontal surface, which means there is no friction.
- Since the blocks are connected by a string, they will have the same acceleration.
- We need to find the tension in the string at points A and B.

Solution:

Step 1: Calculate the acceleration:
- We can use Newton's second law of motion to find the acceleration of the blocks.
- The net force acting on the system is the horizontal force applied (F).
- The total mass of the system is the sum of the masses of blocks A, B, and the string (m1 + m2 + m3).
- Using the formula F = ma, we can write: F = (m1 + m2 + m3) * a
- Substituting the given values, we get: 8 = (1 + 2 + 1) * a
- Simplifying the equation, we have: 8 = 4a
- Dividing both sides by 4, we find: a = 2 m/s²

Step 2: Calculate the tension at point A:
- Since block A is being pulled by the force (F), the tension at point A will be equal to the force applied.
- Therefore, the tension at point A is 8 N.

Step 3: Calculate the tension at point B:
- To find the tension at point B, we need to consider the forces acting on block B.
- The only force acting on block B is the tension in the string.
- According to Newton's second law, the net force on block B is equal to the mass of block B multiplied by its acceleration.
- The mass of block B is 2 kg and the acceleration is 2 m/s² (as calculated in step 1).
- So, the net force on block B is 2 * 2 = 4 N.
- Since the tension in the string is the force acting on block B, the tension at point B is 4 N.

Summary:
- The tension in the string at point A is 8 N and at point B is 4 N. The blocks have an acceleration of 2 m/s², and the force applied is 8 N.

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