An object is projected vertically upward with speed √gR where R is radius of earth and g acc. due to gravity on the surface of earth. find the max. height attained by it......plzz tell...

Question

Answer

By conservation of mechanical energy we have,

(P.E. + K.E.) on the surface of earth = Total energy on a height h attained by it.

or -GMm/R + 1/2mv^2 = -GMm/R+h

or 1/2 m(√gr)^2 = GMm (1/R - 1/R+h)

or gr/2 = GM x h/R(R+h)

or h = R+h/2

or 2h = R+h

or h = R

And hence, the maximum height attained by the object is R.

I hope it is helpful.

Cheers! :)

Answer

R/2

Answer

Problem: An object is projected vertically upward with speed √gR where R is radius of earth and g acc. due to gravity on the surface of earth. Find the max. height attained by it.

Solution:
To solve the problem, we can use the equations of motion under gravity.

Step 1: Find the initial velocity (u) of the object.

The initial velocity (u) of the object is given as √gR.

Step 2: Find the final velocity (v) of the object.

At the highest point, the final velocity (v) of the object is zero.

Step 3: Find the time (t) taken by the object to reach the highest point.

We can use the equation v = u - gt, where g is the acceleration due to gravity.

At the highest point, v = 0. Therefore,

0 = √gR - gt

t = √(gR)/g

Step 4: Find the maximum height (h) attained by the object.

We can use the equation h = ut - 1/2gt^2, where u is the initial velocity and t is the time taken to reach the highest point.

Substituting the values of u and t, we get

h = √gR * √(gR)/g - 1/2g(√(gR)/g)^2

h = R + R/2

Therefore, the maximum height attained by the object is 3R/2.

Answer

intial velocity is √gR when object will go vertically upwards final velocity will become 0 at max height according to formula v^2-u^2 =2as v =0 and u= √gR and acceleration will be g so put the values in the formula and take out value of s which is max height

Answer

no it's answer is R.....but I don't know how is it...

Answer

Yes R/2 ..

Answer

Guessing that √gR is the same as √g√Rv^2 - u^2 = 2asTaking downwards as negative we get,v = 0 u = -√gRs = ?a = -gi.e, 0-(-√gR)^2=2*-gs-gR=-2gss=R/2If my assumption is wrong and by √gR you meant R√g than the answer is s=(R^2)/2p.s I am in eleventh so there may be mistakes

Answer

R

Answer

r/2

Answer

R/2
since the total kinetic energy will change into potential energy
as
Ke=1/2 m v^2 =mgh
putting v^2=gR
1/2 mgR=mgh
so R/2=h

Answer

R/2

Answer

how.......plZ TELL me solution.........of ur answer......

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