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A man weighing 80 kg, stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of 5m/s2. What would be the reading on the scale ? (g = 10 m/s2) [2003]
  • a)
    1200 N
  • b)
    zero
  • c)
    400 N
  • d)
    800 N
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A man weighing 80 kg, stands on a weighing scale in a lift which is mo...
Reading of the scale = Apparent wt. of the man = m(g + a) = 80 (10 + 5) = 1200 N
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Most Upvoted Answer
A man weighing 80 kg, stands on a weighing scale in a lift which is mo...
Given data:
- Mass of the man (m) = 80 kg
- Acceleration of the lift (a) = 5 m/s^2
- Acceleration due to gravity (g) = 10 m/s^2

Calculating the reading on the scale:
- The weight of the man can be calculated using the formula:
Weight = mass x acceleration due to gravity
Weight = 80 kg x 10 m/s^2
Weight = 800 N

Calculating the apparent weight of the man in the lift:
- When the lift is moving upwards with an acceleration, the apparent weight of the man changes.
- The apparent weight can be calculated using the formula:
Apparent weight = Weight + (mass x acceleration)
Apparent weight = 800 N + (80 kg x 5 m/s^2)
Apparent weight = 800 N + 400 N
Apparent weight = 1200 N
Therefore, the reading on the scale when the lift is moving upwards with a uniform acceleration of 5 m/s^2 would be 1200 N.
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A man weighing 80 kg, stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of 5m/s2. What would be the reading on the scale ? (g = 10 m/s2) [2003]a)1200 Nb)zeroc)400 Nd)800 NCorrect answer is option 'A'. Can you explain this answer?
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