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A man weighing 80 kg, stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of 5m/s2. What would be the reading on the scale ? (g = 10 m/s2) [2003]
- a)1200 N
- b)zero
- c)400 N
- d)800 N
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A man weighing 80 kg, stands on a weighing scale in a lift which is mo...
Reading of the scale = Apparent wt. of the man = m(g + a) = 80 (10 + 5) = 1200 N
Most Upvoted Answer
A man weighing 80 kg, stands on a weighing scale in a lift which is mo...
Given data:
- Mass of the man (m) = 80 kg
- Acceleration of the lift (a) = 5 m/s^2
- Acceleration due to gravity (g) = 10 m/s^2
Calculating the reading on the scale:
- The weight of the man can be calculated using the formula:
Weight = mass x acceleration due to gravity
Weight = 80 kg x 10 m/s^2
Weight = 800 N
Calculating the apparent weight of the man in the lift:
- When the lift is moving upwards with an acceleration, the apparent weight of the man changes.
- The apparent weight can be calculated using the formula:
Apparent weight = Weight + (mass x acceleration)
Apparent weight = 800 N + (80 kg x 5 m/s^2)
Apparent weight = 800 N + 400 N
Apparent weight = 1200 N
Therefore, the reading on the scale when the lift is moving upwards with a uniform acceleration of 5 m/s^2 would be 1200 N.
- Mass of the man (m) = 80 kg
- Acceleration of the lift (a) = 5 m/s^2
- Acceleration due to gravity (g) = 10 m/s^2
Calculating the reading on the scale:
- The weight of the man can be calculated using the formula:
Weight = mass x acceleration due to gravity
Weight = 80 kg x 10 m/s^2
Weight = 800 N
Calculating the apparent weight of the man in the lift:
- When the lift is moving upwards with an acceleration, the apparent weight of the man changes.
- The apparent weight can be calculated using the formula:
Apparent weight = Weight + (mass x acceleration)
Apparent weight = 800 N + (80 kg x 5 m/s^2)
Apparent weight = 800 N + 400 N
Apparent weight = 1200 N
Therefore, the reading on the scale when the lift is moving upwards with a uniform acceleration of 5 m/s^2 would be 1200 N.
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A man weighing 80 kg, stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of 5m/s2. What would be the reading on the scale ? (g = 10 m/s2) [2003]a)1200 Nb)zeroc)400 Nd)800 NCorrect answer is option 'A'. Can you explain this answer?
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A man weighing 80 kg, stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of 5m/s2. What would be the reading on the scale ? (g = 10 m/s2) [2003]a)1200 Nb)zeroc)400 Nd)800 NCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A man weighing 80 kg, stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of 5m/s2. What would be the reading on the scale ? (g = 10 m/s2) [2003]a)1200 Nb)zeroc)400 Nd)800 NCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A man weighing 80 kg, stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of 5m/s2. What would be the reading on the scale ? (g = 10 m/s2) [2003]a)1200 Nb)zeroc)400 Nd)800 NCorrect answer is option 'A'. Can you explain this answer?.
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