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The average velocity of a body moving with uniform acceleration traveling a distance of 3.06 m is 0.34m/s. If the change in velocity of the body is 0.18m/s during this time, its uniform acceleration is-?
Most Upvoted Answer
The average velocity of a body moving with uniform acceleration travel...
Total time taken = distance/avg speed
= 3.06/0.34 = 9 s
acceleration = change in velocity / time
= 0.18/0.9 = 0.2 ms-2
= 3.06/0.34 = 9 s
acceleration = change in velocity / time
= 0.18/0.9 = 0.2 ms-2
Community Answer
The average velocity of a body moving with uniform acceleration travel...
Given:
Distance traveled (s) = 3.06 m
Average velocity (v) = 0.34 m/s
Change in velocity (Δv) = 0.18 m/s
To find:
Uniform acceleration (a)
Solution:
We can use the equation of motion to find the acceleration of the body.
1. Equation of motion:
The equation of motion relating distance, average velocity, and time is given by:
s = vt
Where:
s = Distance traveled
v = Average velocity
t = Time taken
2. Rearranging the equation:
To find the time taken, we can rearrange the equation as:
t = s/v
3. Substituting the given values:
Substituting the values of distance (s) and average velocity (v) into the equation, we get:
t = 3.06 m / 0.34 m/s
t ≈ 9 seconds
4. Equation of motion with acceleration:
The equation of motion relating velocity, initial velocity, acceleration, and time is given by:
v = u + at
Where:
v = Final velocity
u = Initial velocity
a = Acceleration
t = Time taken
5. Rearranging the equation:
To find the acceleration, we can rearrange the equation as:
a = (v - u)/t
6. Substituting the given values:
Substituting the values of change in velocity (Δv) and time (t) into the equation, we get:
a = Δv / t
a = 0.18 m/s / 9 s
a = 0.02 m/s²
Answer:
The uniform acceleration of the body is 0.02 m/s².
Distance traveled (s) = 3.06 m
Average velocity (v) = 0.34 m/s
Change in velocity (Δv) = 0.18 m/s
To find:
Uniform acceleration (a)
Solution:
We can use the equation of motion to find the acceleration of the body.
1. Equation of motion:
The equation of motion relating distance, average velocity, and time is given by:
s = vt
Where:
s = Distance traveled
v = Average velocity
t = Time taken
2. Rearranging the equation:
To find the time taken, we can rearrange the equation as:
t = s/v
3. Substituting the given values:
Substituting the values of distance (s) and average velocity (v) into the equation, we get:
t = 3.06 m / 0.34 m/s
t ≈ 9 seconds
4. Equation of motion with acceleration:
The equation of motion relating velocity, initial velocity, acceleration, and time is given by:
v = u + at
Where:
v = Final velocity
u = Initial velocity
a = Acceleration
t = Time taken
5. Rearranging the equation:
To find the acceleration, we can rearrange the equation as:
a = (v - u)/t
6. Substituting the given values:
Substituting the values of change in velocity (Δv) and time (t) into the equation, we get:
a = Δv / t
a = 0.18 m/s / 9 s
a = 0.02 m/s²
Answer:
The uniform acceleration of the body is 0.02 m/s².
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The average velocity of a body moving with uniform acceleration traveling a distance of 3.06 m is 0.34m/s. If the change in velocity of the body is 0.18m/s during this time, its uniform acceleration is-?
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The average velocity of a body moving with uniform acceleration traveling a distance of 3.06 m is 0.34m/s. If the change in velocity of the body is 0.18m/s during this time, its uniform acceleration is-? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The average velocity of a body moving with uniform acceleration traveling a distance of 3.06 m is 0.34m/s. If the change in velocity of the body is 0.18m/s during this time, its uniform acceleration is-? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The average velocity of a body moving with uniform acceleration traveling a distance of 3.06 m is 0.34m/s. If the change in velocity of the body is 0.18m/s during this time, its uniform acceleration is-?.
The average velocity of a body moving with uniform acceleration traveling a distance of 3.06 m is 0.34m/s. If the change in velocity of the body is 0.18m/s during this time, its uniform acceleration is-? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The average velocity of a body moving with uniform acceleration traveling a distance of 3.06 m is 0.34m/s. If the change in velocity of the body is 0.18m/s during this time, its uniform acceleration is-? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The average velocity of a body moving with uniform acceleration traveling a distance of 3.06 m is 0.34m/s. If the change in velocity of the body is 0.18m/s during this time, its uniform acceleration is-?.
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