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The distance between two successive atomic planes of a calcite crystal is .3nm.the maximum angle for Bragg's scattering of .3angstrom X-rays will be a)1.43deg b)1.56deg c)2.86deg d)30deg Correct option is c can you explain this?
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The distance between two successive atomic planes of a calcite crystal...
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The distance between two successive atomic planes of a calcite crystal...
Explanation:
To determine the maximum angle for Bragg's scattering, we can use the Bragg's law equation:
2d sin(θ) = nλ
Where:
- 'd' is the distance between two successive atomic planes
- 'θ' is the angle of incidence (or scattering)
- 'n' is the order of the diffraction
- 'λ' is the wavelength of the X-rays
In this case, we are given:
- Distance between two successive atomic planes (d) = 0.3 nm
- Wavelength of X-rays (λ) = 0.3 Å (Angstrom) = 0.03 nm
- Since we are looking for the maximum angle, we can assume the first-order diffraction (n = 1)
Plugging these values into the Bragg's law equation, we get:
2 * 0.3 nm * sin(θ) = 1 * 0.03 nm
Simplifying the equation gives:
sin(θ) = 0.03 nm / (2 * 0.3 nm)
sin(θ) = 0.03 / 0.6
sin(θ) = 0.05
To find the maximum angle, we need to find the inverse sine (arcsine) of 0.05:
θ = arcsin(0.05)
Using a calculator, the approximate value of arcsin(0.05) is 2.86 degrees.
Therefore, the correct option is c) 2.86 degrees.
To determine the maximum angle for Bragg's scattering, we can use the Bragg's law equation:
2d sin(θ) = nλ
Where:
- 'd' is the distance between two successive atomic planes
- 'θ' is the angle of incidence (or scattering)
- 'n' is the order of the diffraction
- 'λ' is the wavelength of the X-rays
In this case, we are given:
- Distance between two successive atomic planes (d) = 0.3 nm
- Wavelength of X-rays (λ) = 0.3 Å (Angstrom) = 0.03 nm
- Since we are looking for the maximum angle, we can assume the first-order diffraction (n = 1)
Plugging these values into the Bragg's law equation, we get:
2 * 0.3 nm * sin(θ) = 1 * 0.03 nm
Simplifying the equation gives:
sin(θ) = 0.03 nm / (2 * 0.3 nm)
sin(θ) = 0.03 / 0.6
sin(θ) = 0.05
To find the maximum angle, we need to find the inverse sine (arcsine) of 0.05:
θ = arcsin(0.05)
Using a calculator, the approximate value of arcsin(0.05) is 2.86 degrees.
Therefore, the correct option is c) 2.86 degrees.
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The distance between two successive atomic planes of a calcite crystal is .3nm.the maximum angle for Bragg's scattering of .3angstrom X-rays will be a)1.43deg b)1.56deg c)2.86deg d)30deg Correct option is c can you explain this?
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The distance between two successive atomic planes of a calcite crystal is .3nm.the maximum angle for Bragg's scattering of .3angstrom X-rays will be a)1.43deg b)1.56deg c)2.86deg d)30deg Correct option is c can you explain this? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The distance between two successive atomic planes of a calcite crystal is .3nm.the maximum angle for Bragg's scattering of .3angstrom X-rays will be a)1.43deg b)1.56deg c)2.86deg d)30deg Correct option is c can you explain this? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The distance between two successive atomic planes of a calcite crystal is .3nm.the maximum angle for Bragg's scattering of .3angstrom X-rays will be a)1.43deg b)1.56deg c)2.86deg d)30deg Correct option is c can you explain this?.
The distance between two successive atomic planes of a calcite crystal is .3nm.the maximum angle for Bragg's scattering of .3angstrom X-rays will be a)1.43deg b)1.56deg c)2.86deg d)30deg Correct option is c can you explain this? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The distance between two successive atomic planes of a calcite crystal is .3nm.the maximum angle for Bragg's scattering of .3angstrom X-rays will be a)1.43deg b)1.56deg c)2.86deg d)30deg Correct option is c can you explain this? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The distance between two successive atomic planes of a calcite crystal is .3nm.the maximum angle for Bragg's scattering of .3angstrom X-rays will be a)1.43deg b)1.56deg c)2.86deg d)30deg Correct option is c can you explain this?.
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