NEET Exam  >  NEET Questions  >  Oxygen gas generated by decomposition of Pota... Start Learning for Free
Oxygen gas generated by decomposition of Potassium chlorate is collected the volume of oxygen collected at 24 degree centigrade and atmospheric pressure of 760 mmhg is 128 ml calculate the mass in gram of Oxygen gas obtained the pressure of a water vapour at 24 degree centigrade is 22.4 mmhg?
Verified Answer
Oxygen gas generated by decomposition of Potassium chlorate is collect...
This question is part of UPSC exam. View all NEET courses
Most Upvoted Answer
Oxygen gas generated by decomposition of Potassium chlorate is collect...
Given information:
- Volume of oxygen collected: 128 ml
- Temperature: 24 degrees Celsius
- Atmospheric pressure: 760 mmHg
- Pressure of water vapor at 24 degrees Celsius: 22.4 mmHg

To find:
Mass of oxygen gas obtained from the decomposition of potassium chlorate.

Explanation:

Step 1: Convert temperature to Kelvin
To convert Celsius to Kelvin, we add 273.15 to the Celsius value.
Temperature in Kelvin = 24 + 273.15 = 297.15 K

Step 2: Convert pressures to atmospheres
Pressure in atmospheres = Pressure in mmHg / 760 (since 1 atm = 760 mmHg)
Atmospheric pressure = 760 mmHg / 760 = 1 atm
Pressure of water vapor = 22.4 mmHg / 760 = 0.0295 atm

Step 3: Calculate the partial pressure of oxygen gas
The total pressure is the sum of the partial pressures of all gases.
Total pressure = atmospheric pressure - pressure of water vapor
Total pressure = 1 atm - 0.0295 atm = 0.9705 atm

Step 4: Apply the ideal gas law
The ideal gas law equation is PV = nRT, where:
P = pressure in atm
V = volume in liters
n = number of moles
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature in Kelvin

Step 5: Convert volume to liters
Volume in liters = 128 ml / 1000 = 0.128 L

Step 6: Rearrange the ideal gas law equation
n = (PV) / (RT)

Step 7: Calculate the number of moles of oxygen gas
n = (0.9705 atm * 0.128 L) / (0.0821 L·atm/mol·K * 297.15 K)

Step 8: Convert moles to grams
To calculate the mass, we need to know the molar mass of oxygen. The molar mass of oxygen is approximately 32 g/mol.

Mass of oxygen gas = n * molar mass of oxygen
Mass of oxygen gas = n * 32 g/mol

Step 9: Calculate the mass of oxygen gas obtained
Substitute the value of n obtained in Step 7 into the equation:
Mass of oxygen gas = (0.9705 atm * 0.128 L) / (0.0821 L·atm/mol·K * 297.15 K) * 32 g/mol

Step 10: Perform the calculations
Calculate the value of the expression to find the mass of oxygen gas obtained. The final value will be in grams.

Final answer:
The mass of oxygen gas obtained from the decomposition of potassium chlorate is the calculated value from Step 10.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
Explore Courses for NEET exam

Top Courses for NEET

Oxygen gas generated by decomposition of Potassium chlorate is collected the volume of oxygen collected at 24 degree centigrade and atmospheric pressure of 760 mmhg is 128 ml calculate the mass in gram of Oxygen gas obtained the pressure of a water vapour at 24 degree centigrade is 22.4 mmhg?
Question Description
Oxygen gas generated by decomposition of Potassium chlorate is collected the volume of oxygen collected at 24 degree centigrade and atmospheric pressure of 760 mmhg is 128 ml calculate the mass in gram of Oxygen gas obtained the pressure of a water vapour at 24 degree centigrade is 22.4 mmhg? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Oxygen gas generated by decomposition of Potassium chlorate is collected the volume of oxygen collected at 24 degree centigrade and atmospheric pressure of 760 mmhg is 128 ml calculate the mass in gram of Oxygen gas obtained the pressure of a water vapour at 24 degree centigrade is 22.4 mmhg? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Oxygen gas generated by decomposition of Potassium chlorate is collected the volume of oxygen collected at 24 degree centigrade and atmospheric pressure of 760 mmhg is 128 ml calculate the mass in gram of Oxygen gas obtained the pressure of a water vapour at 24 degree centigrade is 22.4 mmhg?.
Solutions for Oxygen gas generated by decomposition of Potassium chlorate is collected the volume of oxygen collected at 24 degree centigrade and atmospheric pressure of 760 mmhg is 128 ml calculate the mass in gram of Oxygen gas obtained the pressure of a water vapour at 24 degree centigrade is 22.4 mmhg? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of Oxygen gas generated by decomposition of Potassium chlorate is collected the volume of oxygen collected at 24 degree centigrade and atmospheric pressure of 760 mmhg is 128 ml calculate the mass in gram of Oxygen gas obtained the pressure of a water vapour at 24 degree centigrade is 22.4 mmhg? defined & explained in the simplest way possible. Besides giving the explanation of Oxygen gas generated by decomposition of Potassium chlorate is collected the volume of oxygen collected at 24 degree centigrade and atmospheric pressure of 760 mmhg is 128 ml calculate the mass in gram of Oxygen gas obtained the pressure of a water vapour at 24 degree centigrade is 22.4 mmhg?, a detailed solution for Oxygen gas generated by decomposition of Potassium chlorate is collected the volume of oxygen collected at 24 degree centigrade and atmospheric pressure of 760 mmhg is 128 ml calculate the mass in gram of Oxygen gas obtained the pressure of a water vapour at 24 degree centigrade is 22.4 mmhg? has been provided alongside types of Oxygen gas generated by decomposition of Potassium chlorate is collected the volume of oxygen collected at 24 degree centigrade and atmospheric pressure of 760 mmhg is 128 ml calculate the mass in gram of Oxygen gas obtained the pressure of a water vapour at 24 degree centigrade is 22.4 mmhg? theory, EduRev gives you an ample number of questions to practice Oxygen gas generated by decomposition of Potassium chlorate is collected the volume of oxygen collected at 24 degree centigrade and atmospheric pressure of 760 mmhg is 128 ml calculate the mass in gram of Oxygen gas obtained the pressure of a water vapour at 24 degree centigrade is 22.4 mmhg? tests, examples and also practice NEET tests.
Explore Courses for NEET exam

Top Courses for NEET

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev