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Oxygen gas generated by decomposition of Potassium chlorate is collected the volume of oxygen collected at 24 degree centigrade and atmospheric pressure of 760 mmhg is 128 ml calculate the mass in gram of Oxygen gas obtained the pressure of a water vapour at 24 degree centigrade is 22.4 mmhg?
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Oxygen gas generated by decomposition of Potassium chlorate is collect...
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Oxygen gas generated by decomposition of Potassium chlorate is collect...
Given information:
- Volume of oxygen collected: 128 ml
- Temperature: 24 degrees Celsius
- Atmospheric pressure: 760 mmHg
- Pressure of water vapor at 24 degrees Celsius: 22.4 mmHg
To find:
Mass of oxygen gas obtained from the decomposition of potassium chlorate.
Explanation:
Step 1: Convert temperature to Kelvin
To convert Celsius to Kelvin, we add 273.15 to the Celsius value.
Temperature in Kelvin = 24 + 273.15 = 297.15 K
Step 2: Convert pressures to atmospheres
Pressure in atmospheres = Pressure in mmHg / 760 (since 1 atm = 760 mmHg)
Atmospheric pressure = 760 mmHg / 760 = 1 atm
Pressure of water vapor = 22.4 mmHg / 760 = 0.0295 atm
Step 3: Calculate the partial pressure of oxygen gas
The total pressure is the sum of the partial pressures of all gases.
Total pressure = atmospheric pressure - pressure of water vapor
Total pressure = 1 atm - 0.0295 atm = 0.9705 atm
Step 4: Apply the ideal gas law
The ideal gas law equation is PV = nRT, where:
P = pressure in atm
V = volume in liters
n = number of moles
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature in Kelvin
Step 5: Convert volume to liters
Volume in liters = 128 ml / 1000 = 0.128 L
Step 6: Rearrange the ideal gas law equation
n = (PV) / (RT)
Step 7: Calculate the number of moles of oxygen gas
n = (0.9705 atm * 0.128 L) / (0.0821 L·atm/mol·K * 297.15 K)
Step 8: Convert moles to grams
To calculate the mass, we need to know the molar mass of oxygen. The molar mass of oxygen is approximately 32 g/mol.
Mass of oxygen gas = n * molar mass of oxygen
Mass of oxygen gas = n * 32 g/mol
Step 9: Calculate the mass of oxygen gas obtained
Substitute the value of n obtained in Step 7 into the equation:
Mass of oxygen gas = (0.9705 atm * 0.128 L) / (0.0821 L·atm/mol·K * 297.15 K) * 32 g/mol
Step 10: Perform the calculations
Calculate the value of the expression to find the mass of oxygen gas obtained. The final value will be in grams.
Final answer:
The mass of oxygen gas obtained from the decomposition of potassium chlorate is the calculated value from Step 10.
- Volume of oxygen collected: 128 ml
- Temperature: 24 degrees Celsius
- Atmospheric pressure: 760 mmHg
- Pressure of water vapor at 24 degrees Celsius: 22.4 mmHg
To find:
Mass of oxygen gas obtained from the decomposition of potassium chlorate.
Explanation:
Step 1: Convert temperature to Kelvin
To convert Celsius to Kelvin, we add 273.15 to the Celsius value.
Temperature in Kelvin = 24 + 273.15 = 297.15 K
Step 2: Convert pressures to atmospheres
Pressure in atmospheres = Pressure in mmHg / 760 (since 1 atm = 760 mmHg)
Atmospheric pressure = 760 mmHg / 760 = 1 atm
Pressure of water vapor = 22.4 mmHg / 760 = 0.0295 atm
Step 3: Calculate the partial pressure of oxygen gas
The total pressure is the sum of the partial pressures of all gases.
Total pressure = atmospheric pressure - pressure of water vapor
Total pressure = 1 atm - 0.0295 atm = 0.9705 atm
Step 4: Apply the ideal gas law
The ideal gas law equation is PV = nRT, where:
P = pressure in atm
V = volume in liters
n = number of moles
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature in Kelvin
Step 5: Convert volume to liters
Volume in liters = 128 ml / 1000 = 0.128 L
Step 6: Rearrange the ideal gas law equation
n = (PV) / (RT)
Step 7: Calculate the number of moles of oxygen gas
n = (0.9705 atm * 0.128 L) / (0.0821 L·atm/mol·K * 297.15 K)
Step 8: Convert moles to grams
To calculate the mass, we need to know the molar mass of oxygen. The molar mass of oxygen is approximately 32 g/mol.
Mass of oxygen gas = n * molar mass of oxygen
Mass of oxygen gas = n * 32 g/mol
Step 9: Calculate the mass of oxygen gas obtained
Substitute the value of n obtained in Step 7 into the equation:
Mass of oxygen gas = (0.9705 atm * 0.128 L) / (0.0821 L·atm/mol·K * 297.15 K) * 32 g/mol
Step 10: Perform the calculations
Calculate the value of the expression to find the mass of oxygen gas obtained. The final value will be in grams.
Final answer:
The mass of oxygen gas obtained from the decomposition of potassium chlorate is the calculated value from Step 10.
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Oxygen gas generated by decomposition of Potassium chlorate is collected the volume of oxygen collected at 24 degree centigrade and atmospheric pressure of 760 mmhg is 128 ml calculate the mass in gram of Oxygen gas obtained the pressure of a water vapour at 24 degree centigrade is 22.4 mmhg?
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Oxygen gas generated by decomposition of Potassium chlorate is collected the volume of oxygen collected at 24 degree centigrade and atmospheric pressure of 760 mmhg is 128 ml calculate the mass in gram of Oxygen gas obtained the pressure of a water vapour at 24 degree centigrade is 22.4 mmhg? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Oxygen gas generated by decomposition of Potassium chlorate is collected the volume of oxygen collected at 24 degree centigrade and atmospheric pressure of 760 mmhg is 128 ml calculate the mass in gram of Oxygen gas obtained the pressure of a water vapour at 24 degree centigrade is 22.4 mmhg? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Oxygen gas generated by decomposition of Potassium chlorate is collected the volume of oxygen collected at 24 degree centigrade and atmospheric pressure of 760 mmhg is 128 ml calculate the mass in gram of Oxygen gas obtained the pressure of a water vapour at 24 degree centigrade is 22.4 mmhg?.
Oxygen gas generated by decomposition of Potassium chlorate is collected the volume of oxygen collected at 24 degree centigrade and atmospheric pressure of 760 mmhg is 128 ml calculate the mass in gram of Oxygen gas obtained the pressure of a water vapour at 24 degree centigrade is 22.4 mmhg? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Oxygen gas generated by decomposition of Potassium chlorate is collected the volume of oxygen collected at 24 degree centigrade and atmospheric pressure of 760 mmhg is 128 ml calculate the mass in gram of Oxygen gas obtained the pressure of a water vapour at 24 degree centigrade is 22.4 mmhg? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Oxygen gas generated by decomposition of Potassium chlorate is collected the volume of oxygen collected at 24 degree centigrade and atmospheric pressure of 760 mmhg is 128 ml calculate the mass in gram of Oxygen gas obtained the pressure of a water vapour at 24 degree centigrade is 22.4 mmhg?.
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