NEET Exam  >  NEET Questions  >  A big box at 100 degree centigrade is connect... Start Learning for Free
A big box at 100 degree centigrade is connected to an ice cube through identical metal rods. Ice is melting at the rate of Q1 gram per second. Rods are rearranged so that they are connected in series between box and ice cube. The new rate of melting is Q2 gram per second then Q2/Q1 is equal to?
Most Upvoted Answer
A big box at 100 degree centigrade is connected to an ice cube through...
Introduction:
In this scenario, we have a big box at 100 degrees Celsius connected to an ice cube through identical metal rods. Initially, the ice cube is melting at a rate of Q1 gram per second. The rods are then rearranged in series between the box and the ice cube, and we need to determine the new rate of melting, Q2, in terms of Q1.

Explanation:
To analyze this situation, we need to understand how heat flows through the system. Heat transfer occurs from the higher temperature (the box) to the lower temperature (the ice cube) until thermal equilibrium is reached.

1. Initial Configuration:
Initially, when the rods are connected parallel between the box and the ice cube, the heat flows through both rods simultaneously. This means that the rate of heat transfer through each rod is equal, resulting in an equal rate of melting for the ice cube.

2. Rearranged Configuration:
When the rods are rearranged in series, the heat transfer occurs sequentially through each rod. This means that the rate of heat transfer through each rod is different. The first rod in contact with the box will transfer heat to the second rod, and so on until the final rod in contact with the ice cube.

3. Analysis:
In the initial configuration, where the rods are parallel, the rate of heat transfer is divided equally between the rods. Let's assume this rate as "x" gram per second for each rod. Therefore, the total rate of heat transfer, and hence the rate of melting, is 2x gram per second.

In the rearranged configuration, where the rods are in series, the rate of heat transfer through each rod is different. Let's assume the rate for the first rod as "y" gram per second. As heat flows sequentially through the rods, the rate of heat transfer decreases. Let's assume the rate for the second rod as "z" gram per second.

Therefore, the total rate of heat transfer in the rearranged configuration, and hence the rate of melting, is y + z gram per second.

4. Determining the Ratio:
From the conservation of energy, we know that the total amount of heat transferred in both configurations should be the same. Therefore, we can equate the total rate of heat transfer in both configurations:

2x = y + z

To determine the ratio Q2/Q1, we need to compare the rate of melting in the rearranged configuration (Q2) with the initial rate of melting (Q1).

Q2/Q1 = (y + z)/(2x)

Conclusion:
The ratio Q2/Q1 depends on the specific values of y, z, and 2x. Without additional information about these values, we cannot determine the exact ratio. However, we have established the relationship between the rate of melting in the rearranged configuration (Q2) and the initial rate of melting (Q1) as (y + z)/(2x).
Community Answer
A big box at 100 degree centigrade is connected to an ice cube through...
It will probably depend on the number of rods taken.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
Explore Courses for NEET exam

Top Courses for NEET

A big box at 100 degree centigrade is connected to an ice cube through identical metal rods. Ice is melting at the rate of Q1 gram per second. Rods are rearranged so that they are connected in series between box and ice cube. The new rate of melting is Q2 gram per second then Q2/Q1 is equal to?
Question Description
A big box at 100 degree centigrade is connected to an ice cube through identical metal rods. Ice is melting at the rate of Q1 gram per second. Rods are rearranged so that they are connected in series between box and ice cube. The new rate of melting is Q2 gram per second then Q2/Q1 is equal to? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A big box at 100 degree centigrade is connected to an ice cube through identical metal rods. Ice is melting at the rate of Q1 gram per second. Rods are rearranged so that they are connected in series between box and ice cube. The new rate of melting is Q2 gram per second then Q2/Q1 is equal to? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A big box at 100 degree centigrade is connected to an ice cube through identical metal rods. Ice is melting at the rate of Q1 gram per second. Rods are rearranged so that they are connected in series between box and ice cube. The new rate of melting is Q2 gram per second then Q2/Q1 is equal to?.
Solutions for A big box at 100 degree centigrade is connected to an ice cube through identical metal rods. Ice is melting at the rate of Q1 gram per second. Rods are rearranged so that they are connected in series between box and ice cube. The new rate of melting is Q2 gram per second then Q2/Q1 is equal to? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A big box at 100 degree centigrade is connected to an ice cube through identical metal rods. Ice is melting at the rate of Q1 gram per second. Rods are rearranged so that they are connected in series between box and ice cube. The new rate of melting is Q2 gram per second then Q2/Q1 is equal to? defined & explained in the simplest way possible. Besides giving the explanation of A big box at 100 degree centigrade is connected to an ice cube through identical metal rods. Ice is melting at the rate of Q1 gram per second. Rods are rearranged so that they are connected in series between box and ice cube. The new rate of melting is Q2 gram per second then Q2/Q1 is equal to?, a detailed solution for A big box at 100 degree centigrade is connected to an ice cube through identical metal rods. Ice is melting at the rate of Q1 gram per second. Rods are rearranged so that they are connected in series between box and ice cube. The new rate of melting is Q2 gram per second then Q2/Q1 is equal to? has been provided alongside types of A big box at 100 degree centigrade is connected to an ice cube through identical metal rods. Ice is melting at the rate of Q1 gram per second. Rods are rearranged so that they are connected in series between box and ice cube. The new rate of melting is Q2 gram per second then Q2/Q1 is equal to? theory, EduRev gives you an ample number of questions to practice A big box at 100 degree centigrade is connected to an ice cube through identical metal rods. Ice is melting at the rate of Q1 gram per second. Rods are rearranged so that they are connected in series between box and ice cube. The new rate of melting is Q2 gram per second then Q2/Q1 is equal to? tests, examples and also practice NEET tests.
Explore Courses for NEET exam

Top Courses for NEET

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev