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A particle starts from the origin at t=0 and moves in the x -y plane with constant acceleration a in y direction .it's equation of motion is y=bx^2 .the x component of it's velocityis.√a/2b is correct answer can you explain this answer .?
Most Upvoted Answer
A particle starts from the origin at t=0 and moves in the x -y plane w...
As a= acceleration along y axis, y=1/2 a t²
given y=bx². from these two equations 1/2 a t²=bx².
we get x²=at²/2b.
then x=t√a/2b.
x/t=√a/2b.{x/t=v}
v =√a/2b.
hope you understand this.
given y=bx². from these two equations 1/2 a t²=bx².
we get x²=at²/2b.
then x=t√a/2b.
x/t=√a/2b.{x/t=v}
v =√a/2b.
hope you understand this.
Community Answer
A particle starts from the origin at t=0 and moves in the x -y plane w...
Explanation:
Initial conditions:
- A particle starts from the origin at t=0 and moves in the x-y plane with constant acceleration a in y direction.
- It's equation of motion is y=bx^2.
Deriving the x component of velocity:
- Using the equation of motion, we can find the velocity of the particle in the y direction.
- vy = dy/dt = 2bx(dx/dt)
- Since the acceleration is given to be constant, we can use the following equation to find the x component of velocity:
- vx = (dx/dt) = (1/2a)(d/dt)(vy^2)
- Substituting the value of vy, we get:
- vx = (1/2a)(d/dt)[4b^2x^2(dx/dt)^2]
- vx = (2b/a)(dx/dt)^2
- vx = (2b/a)(2bx)
- vx = 2b^2x/a
Final answer:
- The x component of velocity is given by vx = 2b^2x/a
- At x=0, vx=0
- At x=√(a/2b), vx=√a/2b
Conclusion:
- The x component of velocity of the particle is given by vx = 2b^2x/a.
- At x=0, the x component of velocity is 0.
- At x=√(a/2b), the x component of velocity is √a/2b.
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A particle starts from the origin at t=0 and moves in the x -y plane with constant acceleration a in y direction .it's equation of motion is y=bx^2 .the x component of it's velocityis.√a/2b is correct answer can you explain this answer .?
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A particle starts from the origin at t=0 and moves in the x -y plane with constant acceleration a in y direction .it's equation of motion is y=bx^2 .the x component of it's velocityis.√a/2b is correct answer can you explain this answer .? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A particle starts from the origin at t=0 and moves in the x -y plane with constant acceleration a in y direction .it's equation of motion is y=bx^2 .the x component of it's velocityis.√a/2b is correct answer can you explain this answer .? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle starts from the origin at t=0 and moves in the x -y plane with constant acceleration a in y direction .it's equation of motion is y=bx^2 .the x component of it's velocityis.√a/2b is correct answer can you explain this answer .?.
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