Amount of water produced in the reaction:

To determine the amount of water produced in the reaction, we first need to write the balanced chemical equation for the reaction between hydrogen and oxygen to form water:

2H2 + O2 → 2H2O

From the balanced equation, we can see that 2 moles of hydrogen react with 1 mole of oxygen to produce 2 moles of water.

Now, let's calculate the moles of hydrogen and oxygen present in the reaction:

Moles of hydrogen = mass of hydrogen / molar mass of hydrogen
Moles of hydrogen = 10g / 2g/mol = 5 moles

Moles of oxygen = mass of oxygen / molar mass of oxygen
Moles of oxygen = 64g / 32g/mol = 2 moles

Since the reaction occurs in a 2:1 ratio between hydrogen and oxygen, we can determine that the limiting reactant is oxygen. This means that all of the oxygen will be completely consumed in the reaction, and the amount of water produced will be determined by the moles of oxygen.

Since 1 mole of oxygen produces 2 moles of water, 2 moles of oxygen will produce 4 moles of water.

Now, let's calculate the mass of water produced:

Mass of water = moles of water × molar mass of water
Mass of water = 4 moles × 18g/mol = 72g

Therefore, the amount of water produced in the reaction will be 72g.

In conclusion, when 10g of hydrogen and 64g of oxygen are reacted together, the limiting reactant is oxygen. As a result, 72g of water will be produced in the reaction.

45g