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An engine absorbs heat at temperature of 1000K and rejects heat at 600K. If the engine operates at maximum possible efficiency, the amount of work performed by the amount of work performed by the engine for 200J heat input is (in Joules)
    Correct answer is '80'. Can you explain this answer?
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    An engine absorbs heat at temperature of 1000K and rejects heat at 600...

    =  80J
    The correct answer is: 80
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    An engine absorbs heat at temperature of 1000K and rejects heat at 600...
    Given data:
    - Temperature of heat absorption, T1 = 1000K
    - Temperature of heat rejection, T2 = 600K
    - Heat input, Q1 = 200J

    Explanation:

    1. Efficiency of the engine:
    The efficiency of an engine is given by the Carnot efficiency formula:

    η = 1 - (T2/T1)

    where η is the efficiency, T2 is the temperature of heat rejection, and T1 is the temperature of heat absorption.

    Substituting the given values, we have:

    η = 1 - (600/1000)
    = 1 - 0.6
    = 0.4

    So, the maximum possible efficiency of the engine is 0.4, or 40%.

    2. Work performed by the engine:
    The work performed by an engine is given by the equation:

    W = ηQ1

    where W is the work performed, η is the efficiency of the engine, and Q1 is the heat input.

    Substituting the given values, we have:

    W = 0.4 * 200
    = 80J

    Therefore, the amount of work performed by the engine for a heat input of 200J is 80J.

    Conclusion:
    The engine operates at maximum efficiency and performs 80J of work when given a heat input of 200J.
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    An engine absorbs heat at temperature of 1000K and rejects heat at 600K. If the engine operates at maximum possible efficiency, the amount of work performed by the amount of work performed by the engine for 200J heat input is (in Joules)Correct answer is '80'. Can you explain this answer?
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    An engine absorbs heat at temperature of 1000K and rejects heat at 600K. If the engine operates at maximum possible efficiency, the amount of work performed by the amount of work performed by the engine for 200J heat input is (in Joules)Correct answer is '80'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about An engine absorbs heat at temperature of 1000K and rejects heat at 600K. If the engine operates at maximum possible efficiency, the amount of work performed by the amount of work performed by the engine for 200J heat input is (in Joules)Correct answer is '80'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An engine absorbs heat at temperature of 1000K and rejects heat at 600K. If the engine operates at maximum possible efficiency, the amount of work performed by the amount of work performed by the engine for 200J heat input is (in Joules)Correct answer is '80'. Can you explain this answer?.
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