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If secθ + tanθ = 3, then the value of 
  • a)
    13/7
  • b)
    5/7
  • c)
    1/7
  • d)
    11/7
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
If secθ + tanθ = 3, then the value ofa)13/7b)5/7c)1/7d)11/...
(a – b)2 = a2 + b2 – 2ab
Given that, secθ + tanθ = 3
⇒ secθ = 3 – tanθ
Squaring both side,
⇒ sec2θ = 9 – 6×tan θ + tan2θ
We know that, sec2θ = 1 + tan2θ
∴ 1 + tan2θ = 9 – 6 × tanθ + tan2θ
⇒ 6 × tanθ = 8

Now, we have to calculate 
Putting the value of tan θ
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Most Upvoted Answer
If secθ + tanθ = 3, then the value ofa)13/7b)5/7c)1/7d)11/...
Sec2(theta)-tan2(theta)=1
therefore (sec(theta)+tan(theta))X(sec(theta)-tan(theta))=3

therefore sec(theta)-tan(theta)=1/3
by further solving above ,
3sin(theta)+cos(theta)=3 eq 1

and, by solving sec(theta)+tan(theta)=3,you will get,
3cos(theta)-sin(theta)=1 eq 2

by solving eq 1 and eq 2,we get
sin(theta)=4/5 and cos(theta)=3/5
therefore tan(theta)=4/3
by putting this value,you get,

(tan(theta)-1)/(tan(theta)+1)=1/7 i.e option C
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If secθ + tanθ = 3, then the value ofa)13/7b)5/7c)1/7d)11/7Correct answer is option 'C'. Can you explain this answer?
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