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In an examination, a student gets 20% of total marks and fails by 30 marks. Another student gets 32% of total marks which is more than the minimum pass marks by 42 marks. The pass percentage is
- a)24%
- b)25%
- c)26%
- d)28%
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
In an examination, a student gets 20% of total marks and fails by 30 m...
Let the total marks be X
Then, marks obtained by student 1 = 0.2X
Since, student 1 fails by 30 marks after getting 20% marks
∴ According to student1, Passing marks = 0.2X + 30
Similarly, Marks obtained by student 2 = 0.32X
And according to student 2, passing marks = 0.32X - 42;
Equating eq. 1 and 2, we get
0.2X + 30 = 0.32X - 42
⇒ X = 600
∴ Passing marks = (0.2 × 600) + 30 = 150
Passing marks %
Hence, the passing marks are 25%.
Then, marks obtained by student 1 = 0.2X
Since, student 1 fails by 30 marks after getting 20% marks
∴ According to student1, Passing marks = 0.2X + 30
Similarly, Marks obtained by student 2 = 0.32X
And according to student 2, passing marks = 0.32X - 42;
Equating eq. 1 and 2, we get
0.2X + 30 = 0.32X - 42
⇒ X = 600
∴ Passing marks = (0.2 × 600) + 30 = 150
Passing marks %
Hence, the passing marks are 25%.
Most Upvoted Answer
In an examination, a student gets 20% of total marks and fails by 30 m...
Solution:
Let's assume the total marks of the exam as 'x'.
First Student:
Marks obtained by the first student = 20% of x
Total marks = x
But, the student fails by 30 marks
Therefore, 20% of x - 30 = Marks obtained by the student
=> (20/100)x - 30 = (20x - 300)/100
=> 20x - 300 = 100[(20/100)x - 30]
=> 20x - 300 = 2x - 3000
=> 18x = 2700
=> x = 150
Second Student:
Marks obtained by the second student = 32% of x
Minimum passing marks = 20% of x
But, the student gets 42 marks more than the minimum passing marks.
Therefore, 32% of x - 20% of x = 42
=> (32-20)/100 x = 42
=> 12/100 x = 42
=> x = 350
Pass Percentage:
Minimum passing marks = 20% of x = 20% of 350 = 70
Pass percentage = (Total marks obtained by the second student / Total marks) x 100
= (112/350) x 100
= 32%
But, the question asks for the pass percentage, which is more than the minimum pass marks by 42 marks. Therefore, we need to subtract 42 marks from the total marks obtained by the second student to get the minimum passing marks.
Pass percentage = (Total marks obtained by the second student - 42)/Total marks x 100
= (112-42)/350 x 100
= 70/350 x 100
= 20%
Hence, the pass percentage is 20%, which is option B.
Let's assume the total marks of the exam as 'x'.
First Student:
Marks obtained by the first student = 20% of x
Total marks = x
But, the student fails by 30 marks
Therefore, 20% of x - 30 = Marks obtained by the student
=> (20/100)x - 30 = (20x - 300)/100
=> 20x - 300 = 100[(20/100)x - 30]
=> 20x - 300 = 2x - 3000
=> 18x = 2700
=> x = 150
Second Student:
Marks obtained by the second student = 32% of x
Minimum passing marks = 20% of x
But, the student gets 42 marks more than the minimum passing marks.
Therefore, 32% of x - 20% of x = 42
=> (32-20)/100 x = 42
=> 12/100 x = 42
=> x = 350
Pass Percentage:
Minimum passing marks = 20% of x = 20% of 350 = 70
Pass percentage = (Total marks obtained by the second student / Total marks) x 100
= (112/350) x 100
= 32%
But, the question asks for the pass percentage, which is more than the minimum pass marks by 42 marks. Therefore, we need to subtract 42 marks from the total marks obtained by the second student to get the minimum passing marks.
Pass percentage = (Total marks obtained by the second student - 42)/Total marks x 100
= (112-42)/350 x 100
= 70/350 x 100
= 20%
Hence, the pass percentage is 20%, which is option B.
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In an examination, a student gets 20% of total marks and fails by 30 marks. Another student gets 32% of total marks which is more than the minimum pass marks by 42 marks. The pass percentage isa)24%b)25%c)26%d)28%Correct answer is option 'B'. Can you explain this answer?
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