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For the above question, the probability that there is at least one tail is:
- a)2/3
- b)7/8
- c)3/8
- d)1/2
Correct answer is option 'B'. Can you explain this answer?
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For the above question, the probability that there is at least one tai...
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For the above question, the probability that there is at least one tai...
Solution:
We have to find the probability of getting at least one tail when a coin is tossed three times.
To solve this problem, we can use the complement rule of probability. The complement of an event A is the event that A does not occur. So, the probability of the complement of event A is equal to 1 minus the probability of event A.
Let's find the probability of the complement of event A, which is getting no tails when a coin is tossed three times.
Probability of getting no tails in one toss = 1/2
Probability of getting no tails in three tosses = (1/2) x (1/2) x (1/2) = 1/8
Therefore, the probability of getting at least one tail in three tosses is:
P(A) = 1 - P(complement of A)
P(A) = 1 - 1/8
P(A) = 7/8
So, the correct answer is option B) 7/8.
Summary:
- We used the complement rule of probability to solve this problem.
- The probability of the complement of event A is equal to 1 minus the probability of event A.
- We found the probability of the complement of event A, which is getting no tails in three tosses.
- We subtracted the probability of the complement of event A from 1 to find the probability of event A, which is getting at least one tail in three tosses.
- The answer is option B) 7/8.
We have to find the probability of getting at least one tail when a coin is tossed three times.
To solve this problem, we can use the complement rule of probability. The complement of an event A is the event that A does not occur. So, the probability of the complement of event A is equal to 1 minus the probability of event A.
Let's find the probability of the complement of event A, which is getting no tails when a coin is tossed three times.
Probability of getting no tails in one toss = 1/2
Probability of getting no tails in three tosses = (1/2) x (1/2) x (1/2) = 1/8
Therefore, the probability of getting at least one tail in three tosses is:
P(A) = 1 - P(complement of A)
P(A) = 1 - 1/8
P(A) = 7/8
So, the correct answer is option B) 7/8.
Summary:
- We used the complement rule of probability to solve this problem.
- The probability of the complement of event A is equal to 1 minus the probability of event A.
- We found the probability of the complement of event A, which is getting no tails in three tosses.
- We subtracted the probability of the complement of event A from 1 to find the probability of event A, which is getting at least one tail in three tosses.
- The answer is option B) 7/8.
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For the above question, the probability that there is at least one tail is:a)2/3b)7/8c)3/8d)1/2Correct answer is option 'B'. Can you explain this answer?
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