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A container contains mixture of milk and water in the ratio of 4 : 7. 8 litres of this mixture is replaced by water. The new ratio of milk and water becomes 4 : 9. Find the initial quantity of water in the mixture.
  • a)
    364/11
  • b)
    363/11
  • c)
    354/11
  • d)
    312/13
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A container contains mixture of milk and water in the ratio of 4 : 7. ...
Given, container contains mixture of milk and water in the ratio of 4 : 7.
Let the volume of milk and water be 4a and 7a.
Now, 8 litres are removed and replaced by water.
In 1 litre of mixture has 4/11 litres of milk and 7/11 litres of water are present.
Thus in 8 litres 32/11 and 56/11 litres of milk and water are present.
∴ Volume of milk = 4a – 32/11
Volume of water = 7a – 56/11 + 8
New ratio = 4 : 9

⇒ a = 52/11
Now, initial amount of water = 7a = 364/11
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Most Upvoted Answer
A container contains mixture of milk and water in the ratio of 4 : 7. ...
Given:
Initial ratio of milk and water = 4 : 7
New ratio of milk and water = 4 : 9
Total quantity of mixture = 8 litres

Let's assume:
Initial quantity of milk = 4x
Initial quantity of water = 7x

After replacement, the quantity of milk remains the same:
4x = 4/13 * (8 litres)

Calculating x:
x = 8*13/52
x = 2 litres

Initial quantity of water:
7x = 7 * 2 = 14 litres
Therefore, the initial quantity of water in the mixture was 14 litres, which is equal to 364/11 when expressed as a fraction. So, option (a) is correct.
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A container contains mixture of milk and water in the ratio of 4 : 7. 8 litres of this mixture is replaced by water. The new ratio of milk and water becomes 4 : 9. Find the initial quantity of water in the mixture.a)364/11b)363/11c)354/11d)312/13Correct answer is option 'A'. Can you explain this answer?
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