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1.3 litre of Oxygen gas at 1 ATM and 300 kelvin is exposed to a solid surface of 3 gram in a container after complete adsorption the pressure of oxygen is reduced to 0.7 ATM calculate the value of x/m?
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Calculation of x/m in Oxygen Gas Adsorption

Given Data:


  • Initial volume of Oxygen gas (Vi) = 1.3 L

  • Initial pressure of Oxygen gas (Pi) = 1 ATM

  • Final pressure of Oxygen gas (Pf) = 0.7 ATM

  • Temperature of Oxygen gas (T) = 300 K

  • Mass of adsorbent (m) = 3 g



Formula Used:

The amount of gas adsorbed (x) per unit mass of adsorbent (m) can be calculated using the following formula:

x/m = (1/Vi) * ln [(Pi - Pf) / Pf]

where,
ln = natural logarithm

Calculation:

Substituting the given values in the formula, we get:

x/m = (1/1.3) * ln [(1 - 0.7) / 0.7]
x/m = 0.769 * ln (0.4286)
x/m = 0.769 * (-0.8474)
x/m = -0.6529

Since x/m cannot be negative, we take the absolute value of the result.

x/m = 0.6529

Therefore, the value of x/m in the given oxygen gas adsorption problem is 0.6529.

Explanation:

The given problem deals with the adsorption of oxygen gas on a solid surface. The initial volume and pressure of the gas are given, and after complete adsorption, the pressure is reduced to a certain value. The amount of gas adsorbed per unit mass of adsorbent can be calculated using the formula x/m = (1/Vi) * ln [(Pi - Pf) / Pf].

This formula is derived from the ideal gas law and the Langmuir adsorption isotherm. The natural logarithm is used to account for the non-linear relationship between pressure and the amount of gas adsorbed. The value of x/m obtained from this formula gives an idea of the efficiency of the adsorbent in removing the gas from the system. In this case, we get a value of 0.6529, which means that the adsorbent is able to adsorb 0.6529 moles of oxygen gas per unit mass of adsorbent.
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Read the passage given below and answer the following questions:Adsorption depends on the nature of the adsorbent. The rough solid surface has more number of pores and adsorb more number of gases than the smooth surface. Most common adsorbents are silica gel, activated charcoal. The extent of adsorption also depends on the surface area of solid. Specific surface area of an adsorbent is the surface area available for adsorption per gram of the adsorbent. The greater the surface area of the solid, the greater would be the adsoprtion. Charcoal is a more effective adsorbent than solid wood. Desorption is a process of removing an adsorbed substance from a surface on which it is absorbed.Physisorption is non-specific and any gas can be adsorbed. But the gases which are easily liquefiable (e.g., NH3, HCl, CO2) are adsorbed at a faster rate and to a large extent than the gases which are difficult to liquefy (e.g., H2, O2, N2). It depends on the critical temperature. Higher the critical temperature of a gas, more easily liquefiable it is and more is the rate of adsorption. Chemisorption is specific in nature. Therefore, only those gases can be adsorbed which are capable of forming chemical bonds with the adsorbent.The following questions are multiple choice questions. Choose the most appropriate answer:Q. Select the correct statement regarding desoprtion.

Read the passage given below and answer the following questions:Adsorption depends on the nature of the adsorbent. The rough solid surface has more number of pores and adsorb more number of gases than the smooth surface. Most common adsorbents are silica gel, activated charcoal. The extent of adsorption also depends on the surface area of solid. Specific surface area of an adsorbent is the surface area available for adsorption per gram of the adsorbent. The greater the surface area of the solid, the greater would be the adsoprtion. Charcoal is a more effective adsorbent than solid wood. Desorption is a process of removing an adsorbed substance from a surface on which it is absorbed.Physisorption is non-specific and any gas can be adsorbed. But the gases which are easily liquefiable (e.g., NH3, HCl, CO2) are adsorbed at a faster rate and to a large extent than the gases which are difficult to liquefy (e.g., H2, O2, N2). It depends on the critical temperature. Higher the critical temperature of a gas, more easily liquefiable it is and more is the rate of adsorption. Chemisorption is specific in nature. Therefore, only those gases can be adsorbed which are capable of forming chemical bonds with the adsorbent.The following questions are multiple choice questions. Choose the most appropriate answer:Q. At the same temperature and pressure, select the correct order of adsorption of the following gases on the same mass of charcoal.

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1.3 litre of Oxygen gas at 1 ATM and 300 kelvin is exposed to a solid surface of 3 gram in a container after complete adsorption the pressure of oxygen is reduced to 0.7 ATM calculate the value of x/m?
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