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Q.200c.c of an aqueous solution contains 1.26 gms of a polymer .The osmotic pressure of such solution at 300k is found to be 2.57×10-3 bar.calculate the molar mass of the polymer?if anyone can solve kindly answer it with complete solution
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Q.200c.c of an aqueous solution contains 1.26 gms of a polymer .The os...
I had got approx answer PV=nRT p=2.57 x10^-3V=20 cm^3=200ml=. 2lR=.082bapprox T=300 KAfter substituting Mole n=. 21x10^-4Mole =given mass /molecular mass So MM=given mass /mole =1.26/(.21x10^-4)=60000 g/mole
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Q.200c.c of an aqueous solution contains 1.26 gms of a polymer .The os...
Given data:
- Volume of solution (V) = 200 cc = 0.2 L
- Mass of polymer (m) = 1.26 g
- Osmotic pressure (π) = 2.57 x 10^-3 bar
- Temperature (T) = 300 K
Formula:
The osmotic pressure (π) of a solution is given by the formula:
π = MRT
Where M is the molarity of the solution, R is the ideal gas constant (0.0831 L bar K^-1 mol^-1), and T is the temperature in Kelvin.
Calculation:
First, let's calculate the molarity (M) of the solution using the given mass of the polymer and volume of the solution:
Molarity (M) = (mass of polymer / molar mass of polymer) / volume of solution
M = (1.26 g / molar mass) / 0.2 L
Now, substitute the values of molarity, temperature, and ideal gas constant into the formula for osmotic pressure:
2.57 x 10^-3 = (1.26 / molar mass) * 0.0831 * 300
Solve for the molar mass of the polymer:
molar mass = 1.26 / (2.57 x 10^-3 * 0.0831 * 300)
After solving this expression, you will get the molar mass of the polymer.
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Q.200c.c of an aqueous solution contains 1.26 gms of a polymer .The osmotic pressure of such solution at 300k is found to be 2.57×10-3 bar.calculate the molar mass of the polymer?if anyone can solve kindly answer it with complete solution
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Q.200c.c of an aqueous solution contains 1.26 gms of a polymer .The osmotic pressure of such solution at 300k is found to be 2.57×10-3 bar.calculate the molar mass of the polymer?if anyone can solve kindly answer it with complete solution for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Q.200c.c of an aqueous solution contains 1.26 gms of a polymer .The osmotic pressure of such solution at 300k is found to be 2.57×10-3 bar.calculate the molar mass of the polymer?if anyone can solve kindly answer it with complete solution covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Q.200c.c of an aqueous solution contains 1.26 gms of a polymer .The osmotic pressure of such solution at 300k is found to be 2.57×10-3 bar.calculate the molar mass of the polymer?if anyone can solve kindly answer it with complete solution.
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