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3.5g of a mixture of NaOH and KOH were dissolved and made up to 250 mL. 25 mL of this solution were completely neutralised by 17 mL of (N/2) HCl solution. Then, the percentage of KOH in mixture is?
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3.5g of a mixture of NaOH and KOH were dissolved and made up to 250 mL...
Calculating the Percentage of KOH in Mixture
To calculate the percentage of KOH in the mixture, we need to follow the below steps:
Step 1: Calculate the number of moles of HCl used
We have used 17 mL of (N/2) HCl solution for neutralizing 25 mL of the mixture. The concentration of (N/2) HCl solution is:
(N/2) HCl = (1/2) x 36.5 g/mol = 18.25 g/mol
Now, the number of moles of HCl used can be calculated as:
Number of moles of HCl = (Concentration x Volume) / 1000
Number of moles of HCl = (18.25 x 17) / 1000 = 0.31025 moles
Step 2: Calculate the number of moles of NaOH and KOH in the mixture
Let us assume that the percentage of KOH in the mixture is x%. So, the percentage of NaOH in the mixture will be (100 - x)%.
Now, the number of moles of NaOH and KOH in the mixture can be calculated as:
Number of moles of NaOH = (Weight of NaOH / Molar mass of NaOH)
Number of moles of KOH = (Weight of KOH / Molar mass of KOH)
Weight of NaOH = x/100 x 3.5 g
Weight of KOH = (100 - x)/100 x 3.5 g
Molar mass of NaOH = 40 g/mol
Molar mass of KOH = 56 g/mol
Number of moles of NaOH = (x/100 x 3.5) / 40 = 0.00875 x
Number of moles of KOH = [(100 - x)/100 x 3.5] / 56 = 0.00625 (100 - x)
Step 3: Calculate the number of moles of KOH neutralized by HCl
The number of moles of KOH neutralized by HCl can be calculated by subtracting the number of moles of NaOH from the total number of moles of HCl used:
Number of moles of KOH neutralized = Number of moles of HCl used - Number of moles of NaOH
Number of moles of KOH neutralized = 0.31025 - 0.00875 x
Step 4: Calculate the percentage of KOH in the mixture
Now, we can use the number of moles of KOH neutralized to calculate the percentage of KOH in the mixture:
Number of moles of KOH neutralized = 0.00625
Community Answer
3.5g of a mixture of NaOH and KOH were dissolved and made up to 250 mL...
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3.5g of a mixture of NaOH and KOH were dissolved and made up to 250 mL. 25 mL of this solution were completely neutralised by 17 mL of (N/2) HCl solution. Then, the percentage of KOH in mixture is?
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3.5g of a mixture of NaOH and KOH were dissolved and made up to 250 mL. 25 mL of this solution were completely neutralised by 17 mL of (N/2) HCl solution. Then, the percentage of KOH in mixture is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 3.5g of a mixture of NaOH and KOH were dissolved and made up to 250 mL. 25 mL of this solution were completely neutralised by 17 mL of (N/2) HCl solution. Then, the percentage of KOH in mixture is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 3.5g of a mixture of NaOH and KOH were dissolved and made up to 250 mL. 25 mL of this solution were completely neutralised by 17 mL of (N/2) HCl solution. Then, the percentage of KOH in mixture is?.
3.5g of a mixture of NaOH and KOH were dissolved and made up to 250 mL. 25 mL of this solution were completely neutralised by 17 mL of (N/2) HCl solution. Then, the percentage of KOH in mixture is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 3.5g of a mixture of NaOH and KOH were dissolved and made up to 250 mL. 25 mL of this solution were completely neutralised by 17 mL of (N/2) HCl solution. Then, the percentage of KOH in mixture is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 3.5g of a mixture of NaOH and KOH were dissolved and made up to 250 mL. 25 mL of this solution were completely neutralised by 17 mL of (N/2) HCl solution. Then, the percentage of KOH in mixture is?.
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