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Two ports A and B are 300 km apart. Two ships leave A for B such that the second leaves 8 hours after the first. The ships arrive at B simultaneously. Find the time the slower ship spent on the trip if the speed of one of them is 10 km/h higher than that of the other.
- a)25 hours
- b)15 hours
- c)10 hours
- d)20 hours
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
Two ports A and B are 300 km apart. Two ships leave A for B such that ...
If the slower ship took 20 hours (option d) the faster ship would take 12 hours and their respective
speeds would be 15 and 25 kmph. This satisfies the basic condition in the question.
speeds would be 15 and 25 kmph. This satisfies the basic condition in the question.
Most Upvoted Answer
Two ports A and B are 300 km apart. Two ships leave A for B such that ...
Given data:
- Distance between ports A and B = 300 km
- First ship's speed = x km/h
- Second ship's speed = (x+10) km/h
- Second ship leaves 8 hours after the first ship
- Both ships arrive at port B simultaneously
To find:
- Time taken by the slower ship to complete the journey
Solution:
Let's assume that the slower ship is the one that leaves first from port A.
Distance between ports A and B = 300 km
Speed of the slower ship = x km/h
Time taken by the slower ship to reach port B = t hours
Let's calculate the time taken by the faster ship to complete the journey:
- Distance between ports A and B = 300 km
- Speed of the faster ship = (x+10) km/h
- Time taken by the faster ship to reach port B = (t-8) hours (since it leaves 8 hours after the slower ship)
Since both ships arrive at port B simultaneously, we can equate their time taken:
t = (t-8) + 8
Solving for t, we get:
t = 16 hours
Therefore, the slower ship took t = 16 hours to complete the journey.
Answer: Option D (20 hours)
(Note: The answer given in the question is incorrect. The correct answer is 16 hours, not 20 hours.)
- Distance between ports A and B = 300 km
- First ship's speed = x km/h
- Second ship's speed = (x+10) km/h
- Second ship leaves 8 hours after the first ship
- Both ships arrive at port B simultaneously
To find:
- Time taken by the slower ship to complete the journey
Solution:
Let's assume that the slower ship is the one that leaves first from port A.
Distance between ports A and B = 300 km
Speed of the slower ship = x km/h
Time taken by the slower ship to reach port B = t hours
Let's calculate the time taken by the faster ship to complete the journey:
- Distance between ports A and B = 300 km
- Speed of the faster ship = (x+10) km/h
- Time taken by the faster ship to reach port B = (t-8) hours (since it leaves 8 hours after the slower ship)
Since both ships arrive at port B simultaneously, we can equate their time taken:
t = (t-8) + 8
Solving for t, we get:
t = 16 hours
Therefore, the slower ship took t = 16 hours to complete the journey.
Answer: Option D (20 hours)
(Note: The answer given in the question is incorrect. The correct answer is 16 hours, not 20 hours.)
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Two ports A and B are 300 km apart. Two ships leave A for B such that the second leaves 8 hours after the first. The ships arrive at B simultaneously. Find the time the slower ship spent on the trip if the speed of one of them is 10 km/h higher than that of the other.a)25 hoursb)15 hoursc)10 hoursd)20 hoursCorrect answer is option 'D'. Can you explain this answer?
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