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Two horses started simultaneously towards each other and meet each other 3 h 20 min later. How much time will it take the slower horse to cover the whole distance if the first arrived at the place of departure of the second 5 hours later than the second arrived at the point of departure of thefirst?
- a)10 hours
- b)5 hours
- c)15 hours
- d)6 hours
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Two horses started simultaneously towards each other and meet each oth...
Since the two horses meet after 200 minutes, they cover 0.5% of the distance per minute
(combined) or 30% per hour. This condition is satisfied only if you the slower rider takes 10
hours (thereby covering 10% per hour) and the faster rider takes 5 hours (thereby covering 20%
per hour).
(combined) or 30% per hour. This condition is satisfied only if you the slower rider takes 10
hours (thereby covering 10% per hour) and the faster rider takes 5 hours (thereby covering 20%
per hour).
Most Upvoted Answer
Two horses started simultaneously towards each other and meet each oth...
Given data:
- Two horses started simultaneously towards each other.
- They meet each other 3 h 20 min later.
- The first horse arrived at the place of departure of the second 5 hours later than the second arrived at the point of departure of the first.
To find:
- How much time will it take the slower horse to cover the whole distance?
Solution:
Let us assume the distance between the two horses to be 'd' km.
Let the speed of the faster horse be 'x' km/hr and the speed of the slower horse be 'y' km/hr.
Using the formula, distance = speed × time,
we know that the distance covered by the faster horse in 5 hours is 5x km.
Similarly, the distance covered by the slower horse in 8h 20 min (i.e., 8.33 hours) is 8.33y km.
When the horses meet each other, the total distance covered by them is 'd' km. Thus, we can write the equation as:
5x + 8.33y = d
Also, we know that the time taken by them to meet each other is 3 h 20 min (i.e., 3.33 hours). Using the formula, distance = speed × time, we can write the equation as:
3.33x + 3.33y = d
Solving these two equations, we get:
x = (4d/25) km/hr and y = (3d/25) km/hr
Now, we need to find the time taken by the slower horse to cover the whole distance. Using the formula, time = distance/speed, we can write the equation as:
t = d/y = (25/3) hours = 8 hours 20 minutes
But, we need to find the time taken by the slower horse only. As per the question, the first horse arrived at the place of departure of the second 5 hours later than the second arrived at the point of departure of the first. Thus, the faster horse took 5 + 3.33 = 8.33 hours to cover the distance. Hence, the slower horse took (8h 20min - 8h 20/3min) = 10 hours to cover the whole distance.
Therefore, the correct option is (a) 10 hours.
- Two horses started simultaneously towards each other.
- They meet each other 3 h 20 min later.
- The first horse arrived at the place of departure of the second 5 hours later than the second arrived at the point of departure of the first.
To find:
- How much time will it take the slower horse to cover the whole distance?
Solution:
Let us assume the distance between the two horses to be 'd' km.
Let the speed of the faster horse be 'x' km/hr and the speed of the slower horse be 'y' km/hr.
Using the formula, distance = speed × time,
we know that the distance covered by the faster horse in 5 hours is 5x km.
Similarly, the distance covered by the slower horse in 8h 20 min (i.e., 8.33 hours) is 8.33y km.
When the horses meet each other, the total distance covered by them is 'd' km. Thus, we can write the equation as:
5x + 8.33y = d
Also, we know that the time taken by them to meet each other is 3 h 20 min (i.e., 3.33 hours). Using the formula, distance = speed × time, we can write the equation as:
3.33x + 3.33y = d
Solving these two equations, we get:
x = (4d/25) km/hr and y = (3d/25) km/hr
Now, we need to find the time taken by the slower horse to cover the whole distance. Using the formula, time = distance/speed, we can write the equation as:
t = d/y = (25/3) hours = 8 hours 20 minutes
But, we need to find the time taken by the slower horse only. As per the question, the first horse arrived at the place of departure of the second 5 hours later than the second arrived at the point of departure of the first. Thus, the faster horse took 5 + 3.33 = 8.33 hours to cover the distance. Hence, the slower horse took (8h 20min - 8h 20/3min) = 10 hours to cover the whole distance.
Therefore, the correct option is (a) 10 hours.
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Two horses started simultaneously towards each other and meet each other 3 h 20 min later. How much time will it take the slower horse to cover the whole distance if the first arrived at the place of departure of the second 5 hours later than the second arrived at the point of departure of thefirst?a)10 hoursb)5 hoursc)15 hoursd)6 hoursCorrect answer is option 'A'. Can you explain this answer?
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