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Two oxides of metal contain 50% and 40% of metal M. If the formula of first oxide is MO the formula of 2nd oxide will be?
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Two oxides of metal contain 50% and 40% of metal M. If the formula of ...
Explanation:

Given Information:
- One oxide contains 50% metal M
- One oxide contains 40% metal M
- Formula of the first oxide is MO

Calculating the Oxygen Content:
- Since the first oxide is MO, the remaining 50% is oxygen
- Therefore, the first oxide contains 50% M and 50% O
- Similarly, the second oxide contains 40% M and 60% O

Calculating the Ratio of Metal M:
- To find the formula of the second oxide, we need to determine the ratio of metal M in it
- Let's assume the formula of the second oxide is MOx, where x is the number of metal atoms

Setting up the Equation:
- In the first oxide, the ratio of M to O is 1:1 (MO)
- In the second oxide, the ratio of M to O is x:1 (MOx)
- Set up the equation: 40% M = x / (x + 1) * 100

Solving the Equation:
- 40 = x / (x + 1) * 100
- 40(x + 1) = 100x
- 40x + 40 = 100x
- 60x = 40
- x = 40 / 60
- x = 2/3

Formula of the Second Oxide:
- Therefore, the formula of the second oxide is MO2/3, which simplifies to M2O3
Community Answer
Two oxides of metal contain 50% and 40% of metal M. If the formula of ...
M2O3
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Two oxides of metal contain 50% and 40% of metal M. If the formula of first oxide is MO the formula of 2nd oxide will be?
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