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The sum of the first 16 terms of an AP whose first term and third term are 5 and 15 respectively is
  • a)
    600
  • b)
    765
  • c)
    640
  • d)
    680
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The sum of the first 16 terms of an AP whose first term and third term...
a = 5, a + 2d = 15 means d = 5. The 16th term would be a + 15d = 5 + 75 = 80. The sum of the
series would be given by:
[16/2] × [5 + 80] = 16 × 42.5 = 680. Option (d) is correct.
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The sum of the first 16 terms of an AP whose first term and third term are 5 and 15 respectively isa)600b)765c)640d)680Correct answer is option 'D'. Can you explain this answer?
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