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The 4th and 10th term of an GP are 1/3 and 243 respectively. Find the 2nd term.
- a)3
- b)1
- c)1/27
- d)1/9
Correct answer is option 'C'. Can you explain this answer?
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The 4th and 10th term of an GP are 1/3 and 243 respectively. Find the ...
[Note: To go forward in a G.P. you multiply by the common ratio, to go backward in a G.P. you
divide by the common ratio.]
divide by the common ratio.]
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The 4th and 10th term of an GP are 1/3 and 243 respectively. Find the ...
Given, 4th term = 1/3 and 10th term = 243.
Let the first term be 'a' and the common ratio be 'r'.
We know that the nth term of a GP is given by ar^(n-1).
So, we can write:
ar^3 = 1/3 ...(1)
ar^9 = 243 ...(2)
Dividing equation (2) by equation (1), we get:
r^6 = 729
r = 3
Substituting this value of r in equation (1), we get:
a(3^3) = 1/3
a = 1/27
Therefore, the first term of the GP is 1/27 and the second term can be found using the formula:
ar = (1/27)*3 = 1/9
Hence, the correct answer is option (c) 1/27.
Let the first term be 'a' and the common ratio be 'r'.
We know that the nth term of a GP is given by ar^(n-1).
So, we can write:
ar^3 = 1/3 ...(1)
ar^9 = 243 ...(2)
Dividing equation (2) by equation (1), we get:
r^6 = 729
r = 3
Substituting this value of r in equation (1), we get:
a(3^3) = 1/3
a = 1/27
Therefore, the first term of the GP is 1/27 and the second term can be found using the formula:
ar = (1/27)*3 = 1/9
Hence, the correct answer is option (c) 1/27.
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The 4th and 10th term of an GP are 1/3 and 243 respectively. Find the 2nd term.a)3b)1c)1/27d)1/9Correct answer is option 'C'. Can you explain this answer?
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