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A and B are two mutually exclusive events of an experiment. If P(A') = 0.65, P(A u B) = 0.65 and P(B) = p , find the value o f p.
  • a)
    0.25
  • b)
    0.3
  • c)
    0.1
  • d)
    0.2
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A and B are two mutually exclusive events of an experiment. If P(A'...
P(A) = 1 - 0.65 = 0.35.
Hence, P(B) = 0.65 - 0.35 = 0.3
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Most Upvoted Answer
A and B are two mutually exclusive events of an experiment. If P(A'...
Given: P(A) = 0.65, P(A u B) = 0.65, P(B) = p

Explanation:
We know that A and B are mutually exclusive events which means that they cannot occur together. So, P(A u B) = P(A) + P(B).

Therefore, substituting the given values, we get:
0.65 = P(A) + P(B)
0.65 = 0.65 + P(B)
P(B) = 0

But this contradicts the fact that A and B are mutually exclusive events. So, P(B) cannot be zero.

Hence, we need to recheck our calculations. We know that P(A u B) = P(A) + P(B) - P(A n B).

As A and B are mutually exclusive, P(A n B) = 0. So, we get:
0.65 = 0.65 + P(B) - 0
P(B) = 0

Again, we get P(B) = 0 which contradicts the fact that A and B are mutually exclusive.

Therefore, there is no solution to this problem as the given information is not consistent.

Answer: None of the options (a), (b), (c), (d) are correct.
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A and B are two mutually exclusive events of an experiment. If P(A') = 0.65, P(A u B) = 0.65 and P(B) = p , find the value o f p.a)0.25b)0.3c)0.1d)0.2Correct answer is option 'B'. Can you explain this answer?
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