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At 291k the molar conductivities at infinite dilution of NH4Cl NaOH and NaClare 129.8 217.4 and 108.9Scmsq per mol respectively if the molar conductivity of cent molar solution of NH4Cl is 9.33ScmSq per mol what will be percentage dissociation of NH4OH at this temperature ? Also calculate the dissociation constant of NH4OH? I need only dissociation const?
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At 291k the molar conductivities at infinite dilution of NH4Cl NaOH an...
Percentage Dissociation of NH4OH
To calculate the percentage dissociation of NH4OH, we need to first determine its molar conductivity at infinite dilution. From the given data, we know that the molar conductivity at infinite dilution for NH4Cl is 129.8 S cm²/mol.
The molar conductivity at infinite dilution for NH4OH can be calculated using the Kohlrausch's Law of Independent Migration of Ions. According to this law, the molar conductivity at infinite dilution of an electrolyte is the sum of the molar conductivities of its constituent ions.
NH4OH dissociates into NH4+ and OH- ions. Therefore, the molar conductivity at infinite dilution of NH4OH (Λinf) can be calculated as:
Λinf(NH4OH) = Λinf(NH4+) + Λinf(OH-)
Given that Λinf(NH4Cl) = 129.8 S cm²/mol and Λinf(NaOH) = 217.4 S cm²/mol, we can substitute these values into the equation:
Λinf(NH4OH) = Λinf(NH4+) + Λinf(OH-)
Λinf(NH4OH) = 129.8 + 217.4
Λinf(NH4OH) = 347.2 S cm²/mol
Now, we can calculate the percentage dissociation of NH4OH using the formula:
Percentage Dissociation = (Λcent - Λinf) / Λinf * 100
Given that the molar conductivity of a cent molar solution of NH4Cl (Λcent) is 9.33 S cm²/mol, we can substitute the values into the formula:
Percentage Dissociation = (9.33 - 347.2) / 347.2 * 100
Percentage Dissociation = -337.87 / 347.2 * 100
Percentage Dissociation ≈ -97.26%
Dissociation Constant of NH4OH
The dissociation constant (K) of NH4OH can be calculated using the equation:
K = (Λinf(NH4+) * Λinf(OH-)) / Λinf(NH4OH)
Substituting the given values into the equation:
K = (129.8 * 217.4) / 347.2
K = 81.44
Therefore, the dissociation constant (K) of NH4OH is approximately 81.44.
Explanation
Molar conductivity at infinite dilution (Λinf) is a measure of the conductivity of an electrolyte when it is completely dissociated into ions at infinite dilution. According to Kohlrausch's Law, the molar conductivity at infinite dilution of an electrolyte is the sum of the molar conductivities of its constituent ions.
To calculate the percentage dissociation of NH4OH, we use the molar conductivity at infinite dilution of NH4Cl, NaOH, and NaCl, along with the molar conductivity of a cent molar solution of NH4Cl.
The percentage dissociation of NH4OH is calculated by subtracting the molar conductivity at infinite dilution (Λinf) from the molar conductivity
To calculate the percentage dissociation of NH4OH, we need to first determine its molar conductivity at infinite dilution. From the given data, we know that the molar conductivity at infinite dilution for NH4Cl is 129.8 S cm²/mol.
The molar conductivity at infinite dilution for NH4OH can be calculated using the Kohlrausch's Law of Independent Migration of Ions. According to this law, the molar conductivity at infinite dilution of an electrolyte is the sum of the molar conductivities of its constituent ions.
NH4OH dissociates into NH4+ and OH- ions. Therefore, the molar conductivity at infinite dilution of NH4OH (Λinf) can be calculated as:
Λinf(NH4OH) = Λinf(NH4+) + Λinf(OH-)
Given that Λinf(NH4Cl) = 129.8 S cm²/mol and Λinf(NaOH) = 217.4 S cm²/mol, we can substitute these values into the equation:
Λinf(NH4OH) = Λinf(NH4+) + Λinf(OH-)
Λinf(NH4OH) = 129.8 + 217.4
Λinf(NH4OH) = 347.2 S cm²/mol
Now, we can calculate the percentage dissociation of NH4OH using the formula:
Percentage Dissociation = (Λcent - Λinf) / Λinf * 100
Given that the molar conductivity of a cent molar solution of NH4Cl (Λcent) is 9.33 S cm²/mol, we can substitute the values into the formula:
Percentage Dissociation = (9.33 - 347.2) / 347.2 * 100
Percentage Dissociation = -337.87 / 347.2 * 100
Percentage Dissociation ≈ -97.26%
Dissociation Constant of NH4OH
The dissociation constant (K) of NH4OH can be calculated using the equation:
K = (Λinf(NH4+) * Λinf(OH-)) / Λinf(NH4OH)
Substituting the given values into the equation:
K = (129.8 * 217.4) / 347.2
K = 81.44
Therefore, the dissociation constant (K) of NH4OH is approximately 81.44.
Explanation
Molar conductivity at infinite dilution (Λinf) is a measure of the conductivity of an electrolyte when it is completely dissociated into ions at infinite dilution. According to Kohlrausch's Law, the molar conductivity at infinite dilution of an electrolyte is the sum of the molar conductivities of its constituent ions.
To calculate the percentage dissociation of NH4OH, we use the molar conductivity at infinite dilution of NH4Cl, NaOH, and NaCl, along with the molar conductivity of a cent molar solution of NH4Cl.
The percentage dissociation of NH4OH is calculated by subtracting the molar conductivity at infinite dilution (Λinf) from the molar conductivity
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At 291k the molar conductivities at infinite dilution of NH4Cl NaOH an...
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At 291k the molar conductivities at infinite dilution of NH4Cl NaOH and NaClare 129.8 217.4 and 108.9Scmsq per mol respectively if the molar conductivity of cent molar solution of NH4Cl is 9.33ScmSq per mol what will be percentage dissociation of NH4OH at this temperature ? Also calculate the dissociation constant of NH4OH? I need only dissociation const?
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At 291k the molar conductivities at infinite dilution of NH4Cl NaOH and NaClare 129.8 217.4 and 108.9Scmsq per mol respectively if the molar conductivity of cent molar solution of NH4Cl is 9.33ScmSq per mol what will be percentage dissociation of NH4OH at this temperature ? Also calculate the dissociation constant of NH4OH? I need only dissociation const? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about At 291k the molar conductivities at infinite dilution of NH4Cl NaOH and NaClare 129.8 217.4 and 108.9Scmsq per mol respectively if the molar conductivity of cent molar solution of NH4Cl is 9.33ScmSq per mol what will be percentage dissociation of NH4OH at this temperature ? Also calculate the dissociation constant of NH4OH? I need only dissociation const? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At 291k the molar conductivities at infinite dilution of NH4Cl NaOH and NaClare 129.8 217.4 and 108.9Scmsq per mol respectively if the molar conductivity of cent molar solution of NH4Cl is 9.33ScmSq per mol what will be percentage dissociation of NH4OH at this temperature ? Also calculate the dissociation constant of NH4OH? I need only dissociation const?.
At 291k the molar conductivities at infinite dilution of NH4Cl NaOH and NaClare 129.8 217.4 and 108.9Scmsq per mol respectively if the molar conductivity of cent molar solution of NH4Cl is 9.33ScmSq per mol what will be percentage dissociation of NH4OH at this temperature ? Also calculate the dissociation constant of NH4OH? I need only dissociation const? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about At 291k the molar conductivities at infinite dilution of NH4Cl NaOH and NaClare 129.8 217.4 and 108.9Scmsq per mol respectively if the molar conductivity of cent molar solution of NH4Cl is 9.33ScmSq per mol what will be percentage dissociation of NH4OH at this temperature ? Also calculate the dissociation constant of NH4OH? I need only dissociation const? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At 291k the molar conductivities at infinite dilution of NH4Cl NaOH and NaClare 129.8 217.4 and 108.9Scmsq per mol respectively if the molar conductivity of cent molar solution of NH4Cl is 9.33ScmSq per mol what will be percentage dissociation of NH4OH at this temperature ? Also calculate the dissociation constant of NH4OH? I need only dissociation const?.
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