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If log102 = .301 find log10125.
  • a)
    2.097
  • b)
    2.301
  • c)
    2.10
  • d)
    2.087
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If log102 = .301 find log10125.a)2.097b)2.301c)2.10d)2.087Correct answ...
log10 125 = log10( 1000/8) = log. 1000 - 31og2 = 3 - 3 x 0.301 = 2.097
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Most Upvoted Answer
If log102 = .301 find log10125.a)2.097b)2.301c)2.10d)2.087Correct answ...
Given: log102 = .301
To find: log10125
Solution:
We can use the formula:
logab = logcb / logca

Using this formula, we can write:
log10125 = log210125 / log210

Now, we know that 125 = 5³, therefore:
log210125 = log25³ = 3 log225

And we are given that:
log102 = .301

Using these values, we can substitute in the formula:
log10125 = 3 log225 / log210
log10125 = 3 (log25 / log2) / .301
log10125 = 3 (4.643 / .301)
log10125 = 46.43 / .301
log10125 = 2.097

Therefore, the correct answer is option A) 2.097.
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If log102 = .301 find log10125.a)2.097b)2.301c)2.10d)2.087Correct answer is option 'A'. Can you explain this answer?
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