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What was the day of the week on 26-January-1950?
- a)Monday
- b)Sunday
- c)Thursday
- d)Wednesday
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
What was the day of the week on 26-January-1950?a)Mondayb)Sundayc)Thur...
Formula : (Date + Month code + No.of years + No.of leap year + Century code)/7
=84/7
=5
=Thursday
=84/7
=5
=Thursday
Most Upvoted Answer
What was the day of the week on 26-January-1950?a)Mondayb)Sundayc)Thur...
Calculation of the Day of the Week on 26-January-1950:
- To determine the day of the week on 26-January-1950, we can use the concept of the Zeller's Congruence formula.
- The formula for Zeller's Congruence is:
\[ h = (q + \frac{(13(m+1))}{5} + K + \frac{K}{4} + \frac{J}{4} - 2J) \mod 7 \]
where:
- h is the day of the week (0 = Saturday, 1 = Sunday, 2 = Monday, ..., 6 = Friday)
- q is the day of the month (26 in this case)
- m is the month (January is considered as 13th month of the previous year, so m = 13)
- K is the year of the century (year mod 100 = 50)
- J is the zero-based century (year/100 = 19)
- Substituting the values into the formula:
\[ h = (26 + \frac{(13(13+1))}{5} + 50 + \frac{50}{4} + \frac{19}{4} - 2*19) \mod 7 \]
\[ h = (26 + \frac{182}{5} + 50 + 12.5 + 4.75 - 38) \mod 7 \]
\[ h = (26 + 36.4 + 50 + 12.5 + 4.75 - 38) \mod 7 \]
\[ h = 92.65 \mod 7 \]
\[ h = 1.65 \mod 7 \]
\[ h ≈ 1 \]
- Therefore, the day of the week on 26-January-1950 was Thursday.
- To determine the day of the week on 26-January-1950, we can use the concept of the Zeller's Congruence formula.
- The formula for Zeller's Congruence is:
\[ h = (q + \frac{(13(m+1))}{5} + K + \frac{K}{4} + \frac{J}{4} - 2J) \mod 7 \]
where:
- h is the day of the week (0 = Saturday, 1 = Sunday, 2 = Monday, ..., 6 = Friday)
- q is the day of the month (26 in this case)
- m is the month (January is considered as 13th month of the previous year, so m = 13)
- K is the year of the century (year mod 100 = 50)
- J is the zero-based century (year/100 = 19)
- Substituting the values into the formula:
\[ h = (26 + \frac{(13(13+1))}{5} + 50 + \frac{50}{4} + \frac{19}{4} - 2*19) \mod 7 \]
\[ h = (26 + \frac{182}{5} + 50 + 12.5 + 4.75 - 38) \mod 7 \]
\[ h = (26 + 36.4 + 50 + 12.5 + 4.75 - 38) \mod 7 \]
\[ h = 92.65 \mod 7 \]
\[ h = 1.65 \mod 7 \]
\[ h ≈ 1 \]
- Therefore, the day of the week on 26-January-1950 was Thursday.
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What was the day of the week on 26-January-1950?a)Mondayb)Sundayc)Thursdayd)WednesdayCorrect answer is option 'C'. Can you explain this answer?
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