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Two systems with heat capacities 100cal/gm-K and 200cal/gm-K interact thermally and come to a common temperature 400K. If the initial temperature of system 1 is 500K, what was the initial temperature of systems (in Kelvin) scale
Correct answer is '350'. Can you explain this answer?
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Verified Answer
Two systems with heat capacities 100cal/gm-K and 200cal/gm-K interact ...
Let initial temperature of system 2 is T2. According to conservation of energy, we know that heat released from one system is equal to the heat absorbed by the other system, i.e.
C1 (Tf – T1 ) = C2 (T2 –Tf )
= –50+400
T2 = 350K
The correct answer is: 350
C1 (Tf – T1 ) = C2 (T2 –Tf )
= –50+400
T2 = 350K
The correct answer is: 350
Most Upvoted Answer
Two systems with heat capacities 100cal/gm-K and 200cal/gm-K interact ...
Given Information:
- Heat capacity of system 1 (C1) = 100 cal/gm-K
- Heat capacity of system 2 (C2) = 200 cal/gm-K
- Initial temperature of system 1 (T1) = 500 K
- Common temperature of both systems (Tf) = 400 K
Calculating the final temperature of the mixture:
When two systems interact thermally and reach a common temperature, the heat lost by one system is equal to the heat gained by the other system. This can be expressed using the formula:
Q1 = -Q2
where Q1 is the heat lost by system 1 and Q2 is the heat gained by system 2.
The heat lost by system 1 can be calculated using the formula:
Q1 = C1 * (T1 - Tf)
The heat gained by system 2 can be calculated using the formula:
Q2 = C2 * (Tf - T2)
Since the heat lost by system 1 is equal to the heat gained by system 2, we can equate the two equations:
C1 * (T1 - Tf) = C2 * (Tf - T2)
Substituting the given values:
100 * (500 - 400) = 200 * (400 - T2)
Simplifying the equation:
10000 = 80000 - 200T2
200T2 = 70000
T2 = 70000/200
T2 = 350 K
Conclusion:
The initial temperature of system 2 (T2) was 350 K.
- Heat capacity of system 1 (C1) = 100 cal/gm-K
- Heat capacity of system 2 (C2) = 200 cal/gm-K
- Initial temperature of system 1 (T1) = 500 K
- Common temperature of both systems (Tf) = 400 K
Calculating the final temperature of the mixture:
When two systems interact thermally and reach a common temperature, the heat lost by one system is equal to the heat gained by the other system. This can be expressed using the formula:
Q1 = -Q2
where Q1 is the heat lost by system 1 and Q2 is the heat gained by system 2.
The heat lost by system 1 can be calculated using the formula:
Q1 = C1 * (T1 - Tf)
The heat gained by system 2 can be calculated using the formula:
Q2 = C2 * (Tf - T2)
Since the heat lost by system 1 is equal to the heat gained by system 2, we can equate the two equations:
C1 * (T1 - Tf) = C2 * (Tf - T2)
Substituting the given values:
100 * (500 - 400) = 200 * (400 - T2)
Simplifying the equation:
10000 = 80000 - 200T2
200T2 = 70000
T2 = 70000/200
T2 = 350 K
Conclusion:
The initial temperature of system 2 (T2) was 350 K.
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Two systems with heat capacities 100cal/gm-K and 200cal/gm-K interact thermally and come to a common temperature 400K. If the initial temperature of system 1 is 500K, what was the initial temperature of systems (in Kelvin) scaleCorrect answer is '350'. Can you explain this answer?
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Two systems with heat capacities 100cal/gm-K and 200cal/gm-K interact thermally and come to a common temperature 400K. If the initial temperature of system 1 is 500K, what was the initial temperature of systems (in Kelvin) scaleCorrect answer is '350'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Two systems with heat capacities 100cal/gm-K and 200cal/gm-K interact thermally and come to a common temperature 400K. If the initial temperature of system 1 is 500K, what was the initial temperature of systems (in Kelvin) scaleCorrect answer is '350'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two systems with heat capacities 100cal/gm-K and 200cal/gm-K interact thermally and come to a common temperature 400K. If the initial temperature of system 1 is 500K, what was the initial temperature of systems (in Kelvin) scaleCorrect answer is '350'. Can you explain this answer?.
Two systems with heat capacities 100cal/gm-K and 200cal/gm-K interact thermally and come to a common temperature 400K. If the initial temperature of system 1 is 500K, what was the initial temperature of systems (in Kelvin) scaleCorrect answer is '350'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Two systems with heat capacities 100cal/gm-K and 200cal/gm-K interact thermally and come to a common temperature 400K. If the initial temperature of system 1 is 500K, what was the initial temperature of systems (in Kelvin) scaleCorrect answer is '350'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two systems with heat capacities 100cal/gm-K and 200cal/gm-K interact thermally and come to a common temperature 400K. If the initial temperature of system 1 is 500K, what was the initial temperature of systems (in Kelvin) scaleCorrect answer is '350'. Can you explain this answer?.
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Two systems with heat capacities 100cal/gm-K and 200cal/gm-K interact thermally and come to a common temperature 400K. If the initial temperature of system 1 is 500K, what was the initial temperature of systems (in Kelvin) scaleCorrect answer is '350'. Can you explain this answer?, a detailed solution for Two systems with heat capacities 100cal/gm-K and 200cal/gm-K interact thermally and come to a common temperature 400K. If the initial temperature of system 1 is 500K, what was the initial temperature of systems (in Kelvin) scaleCorrect answer is '350'. Can you explain this answer? has been provided alongside types of Two systems with heat capacities 100cal/gm-K and 200cal/gm-K interact thermally and come to a common temperature 400K. If the initial temperature of system 1 is 500K, what was the initial temperature of systems (in Kelvin) scaleCorrect answer is '350'. Can you explain this answer? theory, EduRev gives you an
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