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In the ΔABC, ∠B = 70° and ∠C = 30°, BO and CO are the angle bisectors of ∠ABC and ∠ACB. Find the value of ∠BOC
- a)125°
- b)130°
- c)145°
- d)155°
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
In the ΔABC, ∠B = 70° and ∠C = 30°, BO and CO ar...
As per the given data
⇒ ∠B = 70° and ∠C = 30°
∴ ∠OBC = 70/2 = 35° and ∠BCO = 30/2 = 15°
We know that sum of the angles in a triangle = 180°
⇒ ∠BOC + ∠OBC + ∠BCO = 180°
⇒ 35 + 15 + ∠BOC = 180°
⇒ ∠BOC = 180 – 50 = 130°
∴ the value of ∠BOC = 130°
⇒ ∠B = 70° and ∠C = 30°
∴ ∠OBC = 70/2 = 35° and ∠BCO = 30/2 = 15°
We know that sum of the angles in a triangle = 180°
⇒ ∠BOC + ∠OBC + ∠BCO = 180°
⇒ 35 + 15 + ∠BOC = 180°
⇒ ∠BOC = 180 – 50 = 130°
∴ the value of ∠BOC = 130°
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In the ΔABC, ∠B = 70° and ∠C = 30°, BO and CO ar...
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In the ΔABC, ∠B = 70° and ∠C = 30°, BO and CO are the angle bisectors of ∠ABC and ∠ACB. Find the value of ∠BOCa)125°b)130°c)145°d)155°Correct answer is option 'B'. Can you explain this answer?
Question Description
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