A tank is filled by three pipes with uniform flow. The first two pipes...
We can not take the value x=3 because, (x−9) becomes negative which is not possible, because the third pipe can fill the tank in (x−9) hours.
Hence, x=15
View all questions of this testA tank is filled by three pipes with uniform flow. The first two pipes...
Analysis:
The key to solving this problem is to understand the relationship between the three pipes and their filling rates.
Let's break down the information given in the question:
- Let the time taken by the first pipe to fill the tank be x hours.
- The second pipe fills the tank 5 hours faster than the first pipe, so it takes x-5 hours.
- The second pipe also fills the tank 4 hours slower than the third pipe, so it takes x+4 hours.
Equation:
Given that the first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe alone, we can set up the following equation:
1/x + 1/(x-5) = 1/(x+4)
Solving the Equation:
- To solve the equation, we first need to find a common denominator.
- Multiplying through by (x)(x-5)(x+4) will simplify the equation.
- After solving the equation, we find that x = 15 hours.
Therefore, the time required by the first pipe to fill the tank is 15 hours.