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A rectangular sheet of metal is 40cm by 15cm. Equal squares of side 5cm are cut off at the corners and the remainder is folded up to form an open rectangular box. The volume of the box is
  • a)
    750cm3
  • b)
    720cm3
  • c)
    680cm3
  • d)
    650cm3
  • e)
    None of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A rectangular sheet of metal is 40cm by 15cm. Equal squares of side 5c...
Length of rectangular sheet = 40 cm
Breadth of rectangular sheet = 15 cm
Since, squares of side 5 cm are cut off from the corner of the sheet.
Therefore, new length = 40 – (5 + 5) cm = 30 cm
new breadth = 15 – (5 + 5) cm = 5 cm
Now, volume of the open box = (30 × 5 × 5) cm3 = 750 cm3
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Most Upvoted Answer
A rectangular sheet of metal is 40cm by 15cm. Equal squares of side 5c...
Problem Overview
A rectangular sheet of metal measuring 40cm by 15cm has squares of 5cm cut from each corner. The remaining structure is then folded to form an open rectangular box.
Dimensions After Cutting
- Original dimensions: 40cm (length) x 15cm (width)
- Size of squares cut: 5cm x 5cm
After cutting the squares, the new dimensions of the box are:
- New length = 40cm - 2(5cm) = 30cm
- New width = 15cm - 2(5cm) = 5cm
- Height of the box = 5cm (the side length of the squares cut)
Calculating the Volume
The volume V of the box can be calculated using the formula:
V = Length x Width x Height
Substituting the new dimensions:
- Length = 30cm
- Width = 5cm
- Height = 5cm
Thus, the volume calculation becomes:
V = 30cm x 5cm x 5cm = 750cm³
Conclusion
The volume of the box formed by folding up the sides after cutting the squares is 750cm³. Therefore, the correct answer is option 'A'.
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A rectangular sheet of metal is 40cm by 15cm. Equal squares of side 5cm are cut off at the corners and the remainder is folded up to form an open rectangular box. The volume of the box isa)750cm3b)720cm3c)680cm3d)650cm3e)None of theseCorrect answer is option 'A'. Can you explain this answer?
Question Description
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