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The photoelectric work function for a metal surface is 4.125 eV. The cut off wavelength for this surface is
- a)4125 Å
- b)2062.5 Å
- c)3000 Å
- d)6000 Å
Correct answer is option 'C'. Can you explain this answer?
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Explanation:
1. Work Function:
- The work function of a metal surface is the minimum amount of energy required to remove an electron from the surface of the metal.
- Given work function = 4.125 eV
2. Relationship with Cut-off Wavelength:
- The cut-off wavelength (λ) is related to the work function (Φ) by the equation: λ = hc/Φ
- Where h is the Planck's constant (4.1357 x 10^-15 eV s) and c is the speed of light (3 x 10^8 m/s).
3. Calculating Cut-off Wavelength:
- Substituting the values in the equation: λ = (4.1357 x 10^-15 eV s * 3 x 10^8 m/s) / 4.125 eV
- λ = (1.24071 x 10^-6 m) / 4.125
- λ = 3 x 10^-7 m
- Converting to Angstroms: 3 x 10^-7 m * 10^10 Å/m = 3000 Å
4. Conclusion:
- The cut-off wavelength for the metal surface with a work function of 4.125 eV is 3000 Å.
- Therefore, the correct answer is option 'C' (3000 Å).
1. Work Function:
- The work function of a metal surface is the minimum amount of energy required to remove an electron from the surface of the metal.
- Given work function = 4.125 eV
2. Relationship with Cut-off Wavelength:
- The cut-off wavelength (λ) is related to the work function (Φ) by the equation: λ = hc/Φ
- Where h is the Planck's constant (4.1357 x 10^-15 eV s) and c is the speed of light (3 x 10^8 m/s).
3. Calculating Cut-off Wavelength:
- Substituting the values in the equation: λ = (4.1357 x 10^-15 eV s * 3 x 10^8 m/s) / 4.125 eV
- λ = (1.24071 x 10^-6 m) / 4.125
- λ = 3 x 10^-7 m
- Converting to Angstroms: 3 x 10^-7 m * 10^10 Å/m = 3000 Å
4. Conclusion:
- The cut-off wavelength for the metal surface with a work function of 4.125 eV is 3000 Å.
- Therefore, the correct answer is option 'C' (3000 Å).
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The photoelectric work function for a metal surface is 4.125 eV. The cut off wavelength for this surface isa)4125 Åb)2062.5 Åc)3000 Åd)6000 ÅCorrect answer is option 'C'. Can you explain this answer?
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