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A photon of wavelength 4000 Å strikes a metal surface, the work function of the metal being 2.13 eV. The kinetic energy of the emitted photolectron is __
- a)0.97 eV
- b)9.7 eV
- c)5.23 eV
- d)3.10 eV
Correct answer is option 'D'. Can you explain this answer?
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A photon of wavelength 4000 Å strikes a metal surface, the work ...
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A photon of wavelength 4000 Å strikes a metal surface, the work ...
Shouldn't A be the answer?
As.. KE=E -- work function
So, 3.10 -- 2.13= 0.97eV
If u agree please report!!
As.. KE=E -- work function
So, 3.10 -- 2.13= 0.97eV
If u agree please report!!
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A photon of wavelength 4000 Å strikes a metal surface, the work ...
Angstroms has an energy of approximately 3.1 eV.
To calculate the energy of a photon, we use the equation:
E = hc / λ
Where:
E is the energy of the photon,
h is Planck's constant (6.626 x 10^-34 J·s),
c is the speed of light (3 x 10^8 m/s),
and λ is the wavelength of the photon.
First, we need to convert the wavelength from angstroms to meters:
4000 angstroms = 4000 x 10^-10 meters
Now we can calculate the energy:
E = (6.626 x 10^-34 J·s) * (3 x 10^8 m/s) / (4000 x 10^-10 meters)
Simplifying the equation:
E = (6.626 x 10^-34 J·s) * (3 x 10^8 m/s) / (4 x 10^-6 meters)
E = (6.626 x 3) / 4 x 10^-34-6 J
E = 19.878 x 10^-28 J
Converting joules to electron volts (eV):
1 eV = 1.6 x 10^-19 J
E = (19.878 x 10^-28 J) / (1.6 x 10^-19 J/eV)
E ≈ 0.1236 eV
Therefore, a photon of wavelength 4000 angstroms has an energy of approximately 0.1236 eV.
To calculate the energy of a photon, we use the equation:
E = hc / λ
Where:
E is the energy of the photon,
h is Planck's constant (6.626 x 10^-34 J·s),
c is the speed of light (3 x 10^8 m/s),
and λ is the wavelength of the photon.
First, we need to convert the wavelength from angstroms to meters:
4000 angstroms = 4000 x 10^-10 meters
Now we can calculate the energy:
E = (6.626 x 10^-34 J·s) * (3 x 10^8 m/s) / (4000 x 10^-10 meters)
Simplifying the equation:
E = (6.626 x 10^-34 J·s) * (3 x 10^8 m/s) / (4 x 10^-6 meters)
E = (6.626 x 3) / 4 x 10^-34-6 J
E = 19.878 x 10^-28 J
Converting joules to electron volts (eV):
1 eV = 1.6 x 10^-19 J
E = (19.878 x 10^-28 J) / (1.6 x 10^-19 J/eV)
E ≈ 0.1236 eV
Therefore, a photon of wavelength 4000 angstroms has an energy of approximately 0.1236 eV.
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A photon of wavelength 4000 Å strikes a metal surface, the work function of the metal being 2.13 eV. The kinetic energy of the emitted photolectron is __a)0.97 eVb)9.7 eVc)5.23 eVd)3.10 eVCorrect answer is option 'D'. Can you explain this answer?
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A photon of wavelength 4000 Å strikes a metal surface, the work function of the metal being 2.13 eV. The kinetic energy of the emitted photolectron is __a)0.97 eVb)9.7 eVc)5.23 eVd)3.10 eVCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A photon of wavelength 4000 Å strikes a metal surface, the work function of the metal being 2.13 eV. The kinetic energy of the emitted photolectron is __a)0.97 eVb)9.7 eVc)5.23 eVd)3.10 eVCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A photon of wavelength 4000 Å strikes a metal surface, the work function of the metal being 2.13 eV. The kinetic energy of the emitted photolectron is __a)0.97 eVb)9.7 eVc)5.23 eVd)3.10 eVCorrect answer is option 'D'. Can you explain this answer?.
A photon of wavelength 4000 Å strikes a metal surface, the work function of the metal being 2.13 eV. The kinetic energy of the emitted photolectron is __a)0.97 eVb)9.7 eVc)5.23 eVd)3.10 eVCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A photon of wavelength 4000 Å strikes a metal surface, the work function of the metal being 2.13 eV. The kinetic energy of the emitted photolectron is __a)0.97 eVb)9.7 eVc)5.23 eVd)3.10 eVCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A photon of wavelength 4000 Å strikes a metal surface, the work function of the metal being 2.13 eV. The kinetic energy of the emitted photolectron is __a)0.97 eVb)9.7 eVc)5.23 eVd)3.10 eVCorrect answer is option 'D'. Can you explain this answer?.
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