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When a photon of energy 4.0 eV strikes the surface of a metal A, the ejected photoelectrons have maximum kinetic energy TA eV and de-Broglie wavelength λA. The maximum kinetic energy of photoelectrons liberated from another metal B by photon of energy 4.50 eV is TB=(TA– 1.5)eV. If the de-Broglie wavelength of these photoelectrons λB = 2λA, then the work function of metal B is:a)4 eVb)2 eVc)1.5 eVd)3 eVCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared
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the NEET exam syllabus. Information about When a photon of energy 4.0 eV strikes the surface of a metal A, the ejected photoelectrons have maximum kinetic energy TA eV and de-Broglie wavelength λA. The maximum kinetic energy of photoelectrons liberated from another metal B by photon of energy 4.50 eV is TB=(TA– 1.5)eV. If the de-Broglie wavelength of these photoelectrons λB = 2λA, then the work function of metal B is:a)4 eVb)2 eVc)1.5 eVd)3 eVCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam.
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Here you can find the meaning of When a photon of energy 4.0 eV strikes the surface of a metal A, the ejected photoelectrons have maximum kinetic energy TA eV and de-Broglie wavelength λA. The maximum kinetic energy of photoelectrons liberated from another metal B by photon of energy 4.50 eV is TB=(TA– 1.5)eV. If the de-Broglie wavelength of these photoelectrons λB = 2λA, then the work function of metal B is:a)4 eVb)2 eVc)1.5 eVd)3 eVCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
When a photon of energy 4.0 eV strikes the surface of a metal A, the ejected photoelectrons have maximum kinetic energy TA eV and de-Broglie wavelength λA. The maximum kinetic energy of photoelectrons liberated from another metal B by photon of energy 4.50 eV is TB=(TA– 1.5)eV. If the de-Broglie wavelength of these photoelectrons λB = 2λA, then the work function of metal B is:a)4 eVb)2 eVc)1.5 eVd)3 eVCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for When a photon of energy 4.0 eV strikes the surface of a metal A, the ejected photoelectrons have maximum kinetic energy TA eV and de-Broglie wavelength λA. The maximum kinetic energy of photoelectrons liberated from another metal B by photon of energy 4.50 eV is TB=(TA– 1.5)eV. If the de-Broglie wavelength of these photoelectrons λB = 2λA, then the work function of metal B is:a)4 eVb)2 eVc)1.5 eVd)3 eVCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of When a photon of energy 4.0 eV strikes the surface of a metal A, the ejected photoelectrons have maximum kinetic energy TA eV and de-Broglie wavelength λA. The maximum kinetic energy of photoelectrons liberated from another metal B by photon of energy 4.50 eV is TB=(TA– 1.5)eV. If the de-Broglie wavelength of these photoelectrons λB = 2λA, then the work function of metal B is:a)4 eVb)2 eVc)1.5 eVd)3 eVCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice When a photon of energy 4.0 eV strikes the surface of a metal A, the ejected photoelectrons have maximum kinetic energy TA eV and de-Broglie wavelength λA. The maximum kinetic energy of photoelectrons liberated from another metal B by photon of energy 4.50 eV is TB=(TA– 1.5)eV. If the de-Broglie wavelength of these photoelectrons λB = 2λA, then the work function of metal B is:a)4 eVb)2 eVc)1.5 eVd)3 eVCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice NEET tests.