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A particle moves with deaceleration along the circle of radius R so that at any moment of time its tangential and normal accelerations are equal in moduli. At the initial moment t = 0 the speed of the particle equals v0, then:(i) the speed of the particle as a function of the distance covered s will be(A) v = v0e_s/R(B) v = v0es/R(C) v = v0e_R/s(D) v = v0eR/s(ii) the total acceleration of the particle as function of velocity and distance covered(A) a =(B) a =(C) a =(D) a =Correct answer is '(i)A,(ii) A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A particle moves with deaceleration along the circle of radius R so that at any moment of time its tangential and normal accelerations are equal in moduli. At the initial moment t = 0 the speed of the particle equals v0, then:(i) the speed of the particle as a function of the distance covered s will be(A) v = v0e_s/R(B) v = v0es/R(C) v = v0e_R/s(D) v = v0eR/s(ii) the total acceleration of the particle as function of velocity and distance covered(A) a =(B) a =(C) a =(D) a =Correct answer is '(i)A,(ii) A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle moves with deaceleration along the circle of radius R so that at any moment of time its tangential and normal accelerations are equal in moduli. At the initial moment t = 0 the speed of the particle equals v0, then:(i) the speed of the particle as a function of the distance covered s will be(A) v = v0e_s/R(B) v = v0es/R(C) v = v0e_R/s(D) v = v0eR/s(ii) the total acceleration of the particle as function of velocity and distance covered(A) a =(B) a =(C) a =(D) a =Correct answer is '(i)A,(ii) A'. Can you explain this answer?.

Solutions for A particle moves with deaceleration along the circle of radius R so that at any moment of time its tangential and normal accelerations are equal in moduli. At the initial moment t = 0 the speed of the particle equals v0, then:(i) the speed of the particle as a function of the distance covered s will be(A) v = v0e_s/R(B) v = v0es/R(C) v = v0e_R/s(D) v = v0eR/s(ii) the total acceleration of the particle as function of velocity and distance covered(A) a =(B) a =(C) a =(D) a =Correct answer is '(i)A,(ii) A'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

Here you can find the meaning of A particle moves with deaceleration along the circle of radius R so that at any moment of time its tangential and normal accelerations are equal in moduli. At the initial moment t = 0 the speed of the particle equals v0, then:(i) the speed of the particle as a function of the distance covered s will be(A) v = v0e_s/R(B) v = v0es/R(C) v = v0e_R/s(D) v = v0eR/s(ii) the total acceleration of the particle as function of velocity and distance covered(A) a =(B) a =(C) a =(D) a =Correct answer is '(i)A,(ii) A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A particle moves with deaceleration along the circle of radius R so that at any moment of time its tangential and normal accelerations are equal in moduli. At the initial moment t = 0 the speed of the particle equals v0, then:(i) the speed of the particle as a function of the distance covered s will be(A) v = v0e_s/R(B) v = v0es/R(C) v = v0e_R/s(D) v = v0eR/s(ii) the total acceleration of the particle as function of velocity and distance covered(A) a =(B) a =(C) a =(D) a =Correct answer is '(i)A,(ii) A'. Can you explain this answer?, a detailed solution for A particle moves with deaceleration along the circle of radius R so that at any moment of time its tangential and normal accelerations are equal in moduli. At the initial moment t = 0 the speed of the particle equals v0, then:(i) the speed of the particle as a function of the distance covered s will be(A) v = v0e_s/R(B) v = v0es/R(C) v = v0e_R/s(D) v = v0eR/s(ii) the total acceleration of the particle as function of velocity and distance covered(A) a =(B) a =(C) a =(D) a =Correct answer is '(i)A,(ii) A'. Can you explain this answer? has been provided alongside types of A particle moves with deaceleration along the circle of radius R so that at any moment of time its tangential and normal accelerations are equal in moduli. At the initial moment t = 0 the speed of the particle equals v0, then:(i) the speed of the particle as a function of the distance covered s will be(A) v = v0e_s/R(B) v = v0es/R(C) v = v0e_R/s(D) v = v0eR/s(ii) the total acceleration of the particle as function of velocity and distance covered(A) a =(B) a =(C) a =(D) a =Correct answer is '(i)A,(ii) A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A particle moves with deaceleration along the circle of radius R so that at any moment of time its tangential and normal accelerations are equal in moduli. At the initial moment t = 0 the speed of the particle equals v0, then:(i) the speed of the particle as a function of the distance covered s will be(A) v = v0e_s/R(B) v = v0es/R(C) v = v0e_R/s(D) v = v0eR/s(ii) the total acceleration of the particle as function of velocity and distance covered(A) a =(B) a =(C) a =(D) a =Correct answer is '(i)A,(ii) A'. Can you explain this answer? tests, examples and also practice NEET tests.