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A man buys milk at the rate of 5 rupees per litre and mixes it with water. By selling the mixture at Rs 4 a litre he gains 25 percent. How much water did each litre of the mixture contain?
- a)9/25
- b)11/25
- c)16/25
- d)19/25
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
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A man buys milk at the rate of 5 rupees per litre and mixes it with wa...
Answer –a) 9/25 Explanation : By rule of allegation Ratio of water: milk = 9:16, so in one litre water will be = 9/25
Most Upvoted Answer
A man buys milk at the rate of 5 rupees per litre and mixes it with wa...
Given:
Cost of milk = Rs 5 per litre
Selling price of mixture = Rs 4 per litre
Profit = 25%
Let the quantity of milk be x litres.
Then, the cost of x litres of milk = Rs 5x
Let the quantity of water be y litres.
Then, the cost of y litres of water = Rs 0 (since water has no cost)
Now, the total cost of (x + y) litres of mixture = Rs (5x + 0) = Rs 5x
Since the man gains 25% profit, the selling price of (x + y) litres of mixture = Rs (5x + 0) + 25% of (5x + 0) = Rs (5x + 1.25x) = Rs 6.25x
According to the given question, the selling price of the mixture is Rs 4 per litre.
So, the total selling price of (x + y) litres of mixture = Rs 4(x + y)
Therefore, Rs 6.25x = Rs 4(x + y)
Simplifying, we get:
2.25x = 4y
x/y = 4/2.25 = 16/9
Hence, the quantity of water in each litre of the mixture = y/(x + y) = 9/25
Therefore, the answer is option A (9/25).
Cost of milk = Rs 5 per litre
Selling price of mixture = Rs 4 per litre
Profit = 25%
Let the quantity of milk be x litres.
Then, the cost of x litres of milk = Rs 5x
Let the quantity of water be y litres.
Then, the cost of y litres of water = Rs 0 (since water has no cost)
Now, the total cost of (x + y) litres of mixture = Rs (5x + 0) = Rs 5x
Since the man gains 25% profit, the selling price of (x + y) litres of mixture = Rs (5x + 0) + 25% of (5x + 0) = Rs (5x + 1.25x) = Rs 6.25x
According to the given question, the selling price of the mixture is Rs 4 per litre.
So, the total selling price of (x + y) litres of mixture = Rs 4(x + y)
Therefore, Rs 6.25x = Rs 4(x + y)
Simplifying, we get:
2.25x = 4y
x/y = 4/2.25 = 16/9
Hence, the quantity of water in each litre of the mixture = y/(x + y) = 9/25
Therefore, the answer is option A (9/25).
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A man buys milk at the rate of 5 rupees per litre and mixes it with water. By selling the mixture at Rs 4 a litre he gains 25 percent. How much water did each litre of the mixture contain?a)9/25b)11/25c)16/25d)19/25e)None of theseCorrect answer is option 'A'. Can you explain this answer?
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