A trader mixes 6ltr of milk costing 5000 rupees with 7ltr of milk costing 6000 rupees per litre. The trader also mixes some quantity of water to the mixture so as to bring the price to 4800 per litre. How many litres of water is addeda)1ltrb)2ltrc)3ltrd)4ltre)None of theseCorrect answer is option 'B'. Can you explain this answer?

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Answer

Hi

Answer

Given information:
- Quantity of milk = 6 liters
- Cost of milk = 5000 rupees
- Quantity of milk = 7 liters
- Cost of milk = 6000 rupees per liter
- Cost of final mixture = 4800 rupees per liter

To find:
The quantity of water added to the mixture.

Let's assume the quantity of water added to the mixture is 'x' liters.

- Total quantity of the mixture = Quantity of milk + Quantity of water
= 6 + 7 + x liters
= 13 + x liters

- Total cost of the mixture = Cost of milk + Cost of water
= (6 * 5000) + (7 * 6000) + (x * 0)
= 30000 + 42000 + 0
= 72000 rupees

- Cost of the mixture per liter = Total cost of the mixture / Total quantity of the mixture
= 72000 / (13 + x)

As per the given information, the cost of the final mixture is 4800 rupees per liter.

Therefore, we can set up the equation:

4800 = 72000 / (13 + x)

To solve this equation for 'x', we can cross-multiply:

4800 * (13 + x) = 72000

Simplifying the equation:

62400 + 4800x = 72000

Subtracting 62400 from both sides:

4800x = 72000 - 62400
= 9600

Dividing both sides by 4800:

x = 9600 / 4800
= 2

Hence, the trader added 2 liters of water to the mixture. Therefore, the correct answer is option B.

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