A vessel is filled with liquid, 4 parts of which are water and 5 parts...
Answer – B.1/10 Explanation : Suppose the vessel initially contains 9litres of liquid.
Let x litres of this liquid be replaced with water. (4-(4x/9) +x) = (5-(5x/9)) X = 9/10
So, part of the mixture replaced = 9/10 * 1/9 = 1/10 Shortcut: 4:5—->9
1:1—->2
8:10
9:9
1/10
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A vessel is filled with liquid, 4 parts of which are water and 5 parts...
Answer – B.1/10 Explanation : Suppose the vessel initially contains 9litres of liquid.
Let x litres of this liquid be replaced with water. (4-(4x/9) +x) = (5-(5x/9)) X = 9/10
So, part of the mixture replaced = 9/10 * 1/9 = 1/10 Shortcut: 4:5—->9
1:1—->2
8:10
9:9
1/10
A vessel is filled with liquid, 4 parts of which are water and 5 parts...
Given:
- A vessel filled with liquid containing 4 parts water and 5 parts syrup.
- We need to find out how much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup.
Approach:
Let's assume that the vessel initially contains 9 liters of the mixture (4 parts water and 5 parts syrup). So, initially, the vessel contains 4/9 * 9 = 4 liters of water and 5/9 * 9 = 5 liters of syrup.
Let's assume that x liters of the mixture is replaced with water. So, after replacing x liters of the mixture with water, the vessel will contain (4 - 4x/9) liters of water and (5 - 5x/9) liters of syrup.
We need to find out the value of x, which will make the ratio of water to syrup equal to 1/1.
Calculation:
- After replacing x liters of the mixture with water, the vessel will contain (4 - 4x/9) liters of water and (5 - 5x/9) liters of syrup.
- As per the question, we need the ratio of water to syrup to be 1/1.
- So, (4 - 4x/9)/(5 - 5x/9) = 1/1
- Therefore, 4 - 4x/9 = 5 - 5x/9
- Solving the above equation, we get x = 1/10.
Therefore, 1/10 liters of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup.
Hence, option B is the correct answer.