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An alloy contains Brass, Iron and Zinc in the ratio 2:3:1 and another contains Iron, zinc and lead in the ratio 5:4:3.If equal weights of both alloys are melted together to form a third alloy, then what will be the weight of lead per kg in new alloy?
  • a)
    5 1/9
  • b)
    1/4
  • c)
    4 1/7
  • d)
    1/8
  • e)
    2/7
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
An alloy contains Brass, Iron and Zinc in the ratio 2:3:1 and another ...
Answer – D.1/8 Explanation : Shortcut: In the first alloy, 2:3:1     =6*2
5:4:3 =12
Multiply 2 to make it equal, 4:6:2
5:4:3
Adding all, 4:11:6:3=24
3/24=1/8
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Most Upvoted Answer
An alloy contains Brass, Iron and Zinc in the ratio 2:3:1 and another ...
Given:
Alloy 1 - Brass:Iron:Zinc = 2:3:1
Alloy 2 - Iron:Zinc:Lead = 5:4:3

Let the weight of each alloy be x.

Step 1: Find the weights of each metal in each alloy
Alloy 1:
Brass = (2/6) x = (1/3) x
Iron = (3/6) x = (1/2) x
Zinc = (1/6) x

Alloy 2:
Iron = (5/12) x
Zinc = (4/12) x = (1/3) x
Lead = (3/12) x = (1/4) x

Step 2: Find the total weight of each metal in the new alloy
Brass = (1/3) x
Iron = (1/2)x + (5/12)x = (7/12)x
Zinc = (1/6)x + (1/3)x = (1/2)x
Lead = (1/4)x

Step 3: Find the ratio of lead to the total weight of the new alloy
Lead : Total weight = (1/4)x : [(1/3)x + (7/12)x + (1/2)x + (1/4)x]
= (1/4)x : (11/12)x
= 1 : (44/11)

Therefore, the weight of lead per kg in the new alloy is 1/8 or option D.
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Community Answer
An alloy contains Brass, Iron and Zinc in the ratio 2:3:1 and another ...
For alloy 1,
let's assume total weight of the first alloy =500g
given, weights of brass, iron and zinc in the ratio =(b:i:z) 2:3:1
so, from this we can say first alloy is divided into 6 parts. i.e 6x parts
then we will get weight of each part as x=1000/6 g.

for alloy 2,
let's assume total weight of the second alloy = 500g
given, weights of iron, zinc and lead in the ratio =(i:z:l) 5:4:3
so, from this we can say second alloy is divided into 12 parts. i.e 12y parts.
then we will get weight of each part as y=1000/12 g.

for alloy1 and alloy2,
x=500/6 g
y=1000/12 g
so, we can say x=2y

for alloy3,
total weight of alloy3= weight of alloy1+weight of alloy2 = 500g + 500g = 1kg

total no of parts used per kg = no of parts of alloy1 + no of parts of alloy2 =6x+12y=6(2y)+2y=24y parts (since x=2y)

no of parts of lead used already=3y parts.

then weight of lead per kg= no of parts of lead used / total no of parts = 3y/24y = 1/8
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An alloy contains Brass, Iron and Zinc in the ratio 2:3:1 and another contains Iron, zinc and lead in the ratio 5:4:3.If equal weights of both alloys are melted together to form a third alloy, then what will be the weight of lead per kg in new alloy?a)5 1/9b)1/4c)4 1/7d)1/8e)2/7Correct answer is option 'D'. Can you explain this answer?
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An alloy contains Brass, Iron and Zinc in the ratio 2:3:1 and another contains Iron, zinc and lead in the ratio 5:4:3.If equal weights of both alloys are melted together to form a third alloy, then what will be the weight of lead per kg in new alloy?a)5 1/9b)1/4c)4 1/7d)1/8e)2/7Correct answer is option 'D'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about An alloy contains Brass, Iron and Zinc in the ratio 2:3:1 and another contains Iron, zinc and lead in the ratio 5:4:3.If equal weights of both alloys are melted together to form a third alloy, then what will be the weight of lead per kg in new alloy?a)5 1/9b)1/4c)4 1/7d)1/8e)2/7Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An alloy contains Brass, Iron and Zinc in the ratio 2:3:1 and another contains Iron, zinc and lead in the ratio 5:4:3.If equal weights of both alloys are melted together to form a third alloy, then what will be the weight of lead per kg in new alloy?a)5 1/9b)1/4c)4 1/7d)1/8e)2/7Correct answer is option 'D'. Can you explain this answer?.
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