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Six litre of milk was taken out from a vessel and is then filled with water. This operation is performed two more times. The ratio of the quantity of milk now left in vessel to that of the water is 8 : 27. How much is the quantity of the milk contained by the vessel originally?
  • a)
    18 litre
  • b)
    16 litre
  • c)
    14 litre
  • d)
    12 litre
  • e)
    None of the Above
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Six litre of milk was taken out from a vessel and is then filled with ...
Answer – A. 18 litre Explanation : [x(1-6/x)/x]³ = (8/27) [x(1-6/x)/x]³ = (2/3)³ (x-6)/x = 2/3 x = 18
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Six litre of milk was taken out from a vessel and is then filled with ...
Given:
- Initially, the vessel contains some quantity of milk.
- 6 litres of milk is taken out from the vessel and replaced with water. This operation is performed two more times.
- The ratio of the quantity of milk now left in the vessel to that of the water is 8:27.

To find:
- The quantity of milk contained by the vessel originally.

Solution:
Let's assume the quantity of milk contained by the vessel originally is 'M' litres.

Step 1: First replacement of milk with water
- 6 litres of milk is taken out from the vessel.
- The quantity of milk remaining in the vessel = M - 6 litres.
- 6 litres of water is added to the vessel.
- The quantity of water in the vessel = 6 litres.
- So, the total quantity of liquid in the vessel = (M - 6) + 6 = M litres.

Step 2: Second replacement of milk with water
- 6 litres of liquid is taken out from the vessel, which contains M litres.
- The quantity of milk remaining in the vessel = M - (6/27)M = (21/27)M.
- 6 litres of water is added to the vessel.
- The quantity of water in the vessel = 6 + (6/27)M = (33/27)M.
- So, the total quantity of liquid in the vessel = (21/27)M + (33/27)M = (54/27)M = 2M litres.

Step 3: Third replacement of milk with water
- 6 litres of liquid is taken out from the vessel, which contains 2M litres.
- The quantity of milk remaining in the vessel = 2M - (6/27)(2M) = (45/27)M.
- 6 litres of water is added to the vessel.
- The quantity of water in the vessel = 6 + (6/27)(2M) = (54/27)M = 2M litres.
- So, the total quantity of liquid in the vessel = (45/27)M + 2M = (135/27)M = 5M litres.

Given:
- The ratio of the quantity of milk now left in the vessel to that of the water is 8:27.
- This means that the quantity of milk now left in the vessel = (8/35) * 5M = (8/7)M.

Equating the quantities of milk:
- The quantity of milk remaining in the vessel = (8/7)M.
- Equating this with the quantity of milk remaining in the vessel after the replacements, we get:
(8/7)M = (45/27)M

Calculating the original quantity of milk:
(8/7)M = (45/27)M
8 * 27 = 45 * 7
216 = 315

This is not possible, so our assumption that the quantity of milk contained by the vessel originally is 'M' litres is incorrect.

Conclusion:
Since our assumption is incorrect, there is no valid solution for the original quantity of milk contained by the vessel
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Six litre of milk was taken out from a vessel and is then filled with water. This operation is performed two more times. The ratio of the quantity of milk now left in vessel to that of the water is 8 : 27. How much is the quantity of the milk contained by the vessel originally?a)18 litreb)16 litrec)14 litred)12 litree)None of the AboveCorrect answer is option 'A'. Can you explain this answer?
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