Six litre of milk was taken out from a vessel and is then filled with ...
Answer – A. 18 litre Explanation : [x(1-6/x)/x]³ = (8/27) [x(1-6/x)/x]³ = (2/3)³ (x-6)/x = 2/3 x = 18
Six litre of milk was taken out from a vessel and is then filled with ...
Given:
- Initially, the vessel contains some quantity of milk.
- 6 litres of milk is taken out from the vessel and replaced with water. This operation is performed two more times.
- The ratio of the quantity of milk now left in the vessel to that of the water is 8:27.
To find:
- The quantity of milk contained by the vessel originally.
Solution:
Let's assume the quantity of milk contained by the vessel originally is 'M' litres.
Step 1: First replacement of milk with water
- 6 litres of milk is taken out from the vessel.
- The quantity of milk remaining in the vessel = M - 6 litres.
- 6 litres of water is added to the vessel.
- The quantity of water in the vessel = 6 litres.
- So, the total quantity of liquid in the vessel = (M - 6) + 6 = M litres.
Step 2: Second replacement of milk with water
- 6 litres of liquid is taken out from the vessel, which contains M litres.
- The quantity of milk remaining in the vessel = M - (6/27)M = (21/27)M.
- 6 litres of water is added to the vessel.
- The quantity of water in the vessel = 6 + (6/27)M = (33/27)M.
- So, the total quantity of liquid in the vessel = (21/27)M + (33/27)M = (54/27)M = 2M litres.
Step 3: Third replacement of milk with water
- 6 litres of liquid is taken out from the vessel, which contains 2M litres.
- The quantity of milk remaining in the vessel = 2M - (6/27)(2M) = (45/27)M.
- 6 litres of water is added to the vessel.
- The quantity of water in the vessel = 6 + (6/27)(2M) = (54/27)M = 2M litres.
- So, the total quantity of liquid in the vessel = (45/27)M + 2M = (135/27)M = 5M litres.
Given:
- The ratio of the quantity of milk now left in the vessel to that of the water is 8:27.
- This means that the quantity of milk now left in the vessel = (8/35) * 5M = (8/7)M.
Equating the quantities of milk:
- The quantity of milk remaining in the vessel = (8/7)M.
- Equating this with the quantity of milk remaining in the vessel after the replacements, we get:
(8/7)M = (45/27)M
Calculating the original quantity of milk:
(8/7)M = (45/27)M
8 * 27 = 45 * 7
216 = 315
This is not possible, so our assumption that the quantity of milk contained by the vessel originally is 'M' litres is incorrect.
Conclusion:
Since our assumption is incorrect, there is no valid solution for the original quantity of milk contained by the vessel