Priya borrows 1000 rupees at the rate of 11% per annum on SI and rahul...
To find the number of years it will take for Priya and Rahul's debts to be equal, we can set up equations for the amounts they owe over time.
Let's start with Priya's debt:
Principal amount = 1000 rupees
Rate of interest = 11% per annum
The formula for Simple Interest (SI) is:
SI = (Principal * Rate * Time) / 100
Let's assume the time taken for the debts to be equal is 't' years.
So, Priya's debt after 't' years will be:
Debt_Priya = Principal + SI = 1000 + (1000 * 11 * t) / 100
Now, let's move on to Rahul's debt:
Principal amount = 780 rupees
Rate of interest = 15% per annum
Rahul's debt after 't' years will be:
Debt_Rahul = Principal + SI = 780 + (780 * 15 * t) / 100
We need to find the value of 't' when Debt_Priya = Debt_Rahul.
Setting the equations equal to each other:
1000 + (1000 * 11 * t) / 100 = 780 + (780 * 15 * t) / 100
To solve this equation, we can simplify it by multiplying through by 100:
100000 + 11000t = 78000 + 11700t
Next, we can simplify further by rearranging the terms:
1100t - 11700t = 78000 - 100000
-10600t = -22000
Dividing both sides by -10600:
t = 22000 / 10600
t = 2.075 years
But the answer options are given in a fraction form. So, let's convert the decimal to fraction.
t = 2.075 years = 2 + 0.075 years
t = 2 + (75/1000) years = 2 + (3/40) years
Thus, the number of years it will take for Priya and Rahul's debts to be equal is 2 + (3/40) years.
The answer closest to this value is option 'A': 31.3/7 years.
Priya borrows 1000 rupees at the rate of 11% per annum on SI and rahul...
Answer –a) 31.3/7 yrs Solution: 1000 + 1000*(11/100)*T = 780 + 780*(15/100)*T