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Six distinghuishable particles are distributed over three non-degenerate levels of energies 0, ∈ and 2∈. The energy of most probable macrostate of the system is _______ ∈.
Correct answer is '6'. Can you explain this answer?
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Six distinghuishable particles are distributed over three non-degenera...
For most probable macrostate particles are distributed equally in all groups.
Energy of the system,
Energy of the system,
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Six distinghuishable particles are distributed over three non-degenera...
1, and 2.
To find the number of ways to distribute the particles, we can use the concept of combinations.
For the first level, we have 6 choices of particles to distribute among the 3 levels. We can represent this as 6C0 (6 choose 0), which is equal to 1 because there is only one way to choose 0 particles for the first level.
For the second level, we have 6 choices of particles to distribute among the 3 levels. We can represent this as 6C1 (6 choose 1), which is equal to 6 because there are six ways to choose 1 particle for the second level.
For the third level, we have 6 choices of particles to distribute among the 3 levels. We can represent this as 6C2 (6 choose 2), which is equal to 15 because there are fifteen ways to choose 2 particles for the third level.
Therefore, the total number of ways to distribute the particles is 1 * 6 * 15 = 90.
So, there are 90 different ways to distribute the six distinguishable particles over the three non-degenerate levels of energies 0, 1, and 2.
To find the number of ways to distribute the particles, we can use the concept of combinations.
For the first level, we have 6 choices of particles to distribute among the 3 levels. We can represent this as 6C0 (6 choose 0), which is equal to 1 because there is only one way to choose 0 particles for the first level.
For the second level, we have 6 choices of particles to distribute among the 3 levels. We can represent this as 6C1 (6 choose 1), which is equal to 6 because there are six ways to choose 1 particle for the second level.
For the third level, we have 6 choices of particles to distribute among the 3 levels. We can represent this as 6C2 (6 choose 2), which is equal to 15 because there are fifteen ways to choose 2 particles for the third level.
Therefore, the total number of ways to distribute the particles is 1 * 6 * 15 = 90.
So, there are 90 different ways to distribute the six distinguishable particles over the three non-degenerate levels of energies 0, 1, and 2.
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Six distinghuishable particles are distributed over three non-degenerate levels of energies 0, ∈ and 2∈. The energy of most probable macrostate of the system is _______∈.Correct answer is '6'. Can you explain this answer?
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